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zordoloom
 one year ago
Best ResponseYou've already chosen the best response.0Are you looking for exact or approximate answers?

akh14
 one year ago
Best ResponseYou've already chosen the best response.0im not sure. it just says solve the following equation. i would guess exact

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{x^2}{3}  \frac{25}{49} = 0\] \[\frac{x^2}{3} = \frac{25}{49} = \frac{5^2}{7^2} = (\frac{5}{7})^2\] Can you solve that for x? Remember, there will be a negative and a positive root.

akh14
 one year ago
Best ResponseYou've already chosen the best response.0im sorry i wrote it wrong the x^2/3 should be x^(2/3)

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0\[x^{2/3}  \frac{25}{49} = 0\] is the real problem?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0That isn't too hard. Move the fraction to the right hand side, and then undo that gnarly exponent. Remember, \(x^{\frac{2}{3}} = \sqrt[3]{x^2}\).

akh14
 one year ago
Best ResponseYou've already chosen the best response.0so now i have x^2= (25/49)^3

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0Yes. Take the square root of the right hand fraction before cubing it, that will be easier!

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0Do you have a final answer?

akh14
 one year ago
Best ResponseYou've already chosen the best response.0no haha i have no idea why take the sqrrt of the right side
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