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zordoloomBest ResponseYou've already chosen the best response.0
Are you looking for exact or approximate answers?
 one year ago

akh14Best ResponseYou've already chosen the best response.0
im not sure. it just says solve the following equation. i would guess exact
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.0
\[\frac{x^2}{3}  \frac{25}{49} = 0\] \[\frac{x^2}{3} = \frac{25}{49} = \frac{5^2}{7^2} = (\frac{5}{7})^2\] Can you solve that for x? Remember, there will be a negative and a positive root.
 one year ago

akh14Best ResponseYou've already chosen the best response.0
im sorry i wrote it wrong the x^2/3 should be x^(2/3)
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.0
\[x^{2/3}  \frac{25}{49} = 0\] is the real problem?
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.0
That isn't too hard. Move the fraction to the right hand side, and then undo that gnarly exponent. Remember, \(x^{\frac{2}{3}} = \sqrt[3]{x^2}\).
 one year ago

akh14Best ResponseYou've already chosen the best response.0
so now i have x^2= (25/49)^3
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.0
Yes. Take the square root of the right hand fraction before cubing it, that will be easier!
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.0
Do you have a final answer?
 one year ago

akh14Best ResponseYou've already chosen the best response.0
no haha i have no idea why take the sqrrt of the right side
 one year ago
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