## anonymous 3 years ago solve x^2/3 - (25/49)=0

1. anonymous

Are you looking for exact or approximate answers?

2. anonymous

im not sure. it just says solve the following equation. i would guess exact

3. whpalmer4

$\frac{x^2}{3} - \frac{25}{49} = 0$ $\frac{x^2}{3} = \frac{25}{49} = \frac{5^2}{7^2} = (\frac{5}{7})^2$ Can you solve that for x? Remember, there will be a negative and a positive root.

4. anonymous

im sorry i wrote it wrong the x^2/3 should be x^(2/3)

5. whpalmer4

$x^{2/3} - \frac{25}{49} = 0$ is the real problem?

6. anonymous

correct

7. whpalmer4

That isn't too hard. Move the fraction to the right hand side, and then undo that gnarly exponent. Remember, $$x^{\frac{2}{3}} = \sqrt[3]{x^2}$$.

8. anonymous

so now i have x^2= (25/49)^3

9. whpalmer4

Yes. Take the square root of the right hand fraction before cubing it, that will be easier!

10. whpalmer4

Do you have a final answer?

11. anonymous

no haha i have no idea why take the sqrrt of the right side