anonymous
  • anonymous
solve x^2/3 - (25/49)=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Are you looking for exact or approximate answers?
anonymous
  • anonymous
im not sure. it just says solve the following equation. i would guess exact
whpalmer4
  • whpalmer4
\[\frac{x^2}{3} - \frac{25}{49} = 0\] \[\frac{x^2}{3} = \frac{25}{49} = \frac{5^2}{7^2} = (\frac{5}{7})^2\] Can you solve that for x? Remember, there will be a negative and a positive root.

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anonymous
  • anonymous
im sorry i wrote it wrong the x^2/3 should be x^(2/3)
whpalmer4
  • whpalmer4
\[x^{2/3} - \frac{25}{49} = 0\] is the real problem?
anonymous
  • anonymous
correct
whpalmer4
  • whpalmer4
That isn't too hard. Move the fraction to the right hand side, and then undo that gnarly exponent. Remember, \(x^{\frac{2}{3}} = \sqrt[3]{x^2}\).
anonymous
  • anonymous
so now i have x^2= (25/49)^3
whpalmer4
  • whpalmer4
Yes. Take the square root of the right hand fraction before cubing it, that will be easier!
whpalmer4
  • whpalmer4
Do you have a final answer?
anonymous
  • anonymous
no haha i have no idea why take the sqrrt of the right side

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