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akh14

  • 3 years ago

solve x^2/3 - (25/49)=0

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  1. zordoloom
    • 3 years ago
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    Are you looking for exact or approximate answers?

  2. akh14
    • 3 years ago
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    im not sure. it just says solve the following equation. i would guess exact

  3. whpalmer4
    • 3 years ago
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    \[\frac{x^2}{3} - \frac{25}{49} = 0\] \[\frac{x^2}{3} = \frac{25}{49} = \frac{5^2}{7^2} = (\frac{5}{7})^2\] Can you solve that for x? Remember, there will be a negative and a positive root.

  4. akh14
    • 3 years ago
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    im sorry i wrote it wrong the x^2/3 should be x^(2/3)

  5. whpalmer4
    • 3 years ago
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    \[x^{2/3} - \frac{25}{49} = 0\] is the real problem?

  6. akh14
    • 3 years ago
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    correct

  7. whpalmer4
    • 3 years ago
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    That isn't too hard. Move the fraction to the right hand side, and then undo that gnarly exponent. Remember, \(x^{\frac{2}{3}} = \sqrt[3]{x^2}\).

  8. akh14
    • 3 years ago
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    so now i have x^2= (25/49)^3

  9. whpalmer4
    • 3 years ago
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    Yes. Take the square root of the right hand fraction before cubing it, that will be easier!

  10. whpalmer4
    • 3 years ago
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    Do you have a final answer?

  11. akh14
    • 3 years ago
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    no haha i have no idea why take the sqrrt of the right side

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