## akh14 Group Title solve x^2/3 - (25/49)=0 one year ago one year ago

1. zordoloom Group Title

Are you looking for exact or approximate answers?

2. akh14 Group Title

im not sure. it just says solve the following equation. i would guess exact

3. whpalmer4 Group Title

$\frac{x^2}{3} - \frac{25}{49} = 0$ $\frac{x^2}{3} = \frac{25}{49} = \frac{5^2}{7^2} = (\frac{5}{7})^2$ Can you solve that for x? Remember, there will be a negative and a positive root.

4. akh14 Group Title

im sorry i wrote it wrong the x^2/3 should be x^(2/3)

5. whpalmer4 Group Title

$x^{2/3} - \frac{25}{49} = 0$ is the real problem?

6. akh14 Group Title

correct

7. whpalmer4 Group Title

That isn't too hard. Move the fraction to the right hand side, and then undo that gnarly exponent. Remember, $$x^{\frac{2}{3}} = \sqrt[3]{x^2}$$.

8. akh14 Group Title

so now i have x^2= (25/49)^3

9. whpalmer4 Group Title

Yes. Take the square root of the right hand fraction before cubing it, that will be easier!

10. whpalmer4 Group Title

Do you have a final answer?

11. akh14 Group Title

no haha i have no idea why take the sqrrt of the right side