solve x^2/3 - (25/49)=0

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solve x^2/3 - (25/49)=0

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Are you looking for exact or approximate answers?
im not sure. it just says solve the following equation. i would guess exact
\[\frac{x^2}{3} - \frac{25}{49} = 0\] \[\frac{x^2}{3} = \frac{25}{49} = \frac{5^2}{7^2} = (\frac{5}{7})^2\] Can you solve that for x? Remember, there will be a negative and a positive root.

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im sorry i wrote it wrong the x^2/3 should be x^(2/3)
\[x^{2/3} - \frac{25}{49} = 0\] is the real problem?
correct
That isn't too hard. Move the fraction to the right hand side, and then undo that gnarly exponent. Remember, \(x^{\frac{2}{3}} = \sqrt[3]{x^2}\).
so now i have x^2= (25/49)^3
Yes. Take the square root of the right hand fraction before cubing it, that will be easier!
Do you have a final answer?
no haha i have no idea why take the sqrrt of the right side

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