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akh14 Group Title

solve x^2/3 - (25/49)=0

  • one year ago
  • one year ago

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  1. zordoloom Group Title
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    Are you looking for exact or approximate answers?

    • one year ago
  2. akh14 Group Title
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    im not sure. it just says solve the following equation. i would guess exact

    • one year ago
  3. whpalmer4 Group Title
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    \[\frac{x^2}{3} - \frac{25}{49} = 0\] \[\frac{x^2}{3} = \frac{25}{49} = \frac{5^2}{7^2} = (\frac{5}{7})^2\] Can you solve that for x? Remember, there will be a negative and a positive root.

    • one year ago
  4. akh14 Group Title
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    im sorry i wrote it wrong the x^2/3 should be x^(2/3)

    • one year ago
  5. whpalmer4 Group Title
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    \[x^{2/3} - \frac{25}{49} = 0\] is the real problem?

    • one year ago
  6. akh14 Group Title
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    correct

    • one year ago
  7. whpalmer4 Group Title
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    That isn't too hard. Move the fraction to the right hand side, and then undo that gnarly exponent. Remember, \(x^{\frac{2}{3}} = \sqrt[3]{x^2}\).

    • one year ago
  8. akh14 Group Title
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    so now i have x^2= (25/49)^3

    • one year ago
  9. whpalmer4 Group Title
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    Yes. Take the square root of the right hand fraction before cubing it, that will be easier!

    • one year ago
  10. whpalmer4 Group Title
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    Do you have a final answer?

    • one year ago
  11. akh14 Group Title
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    no haha i have no idea why take the sqrrt of the right side

    • one year ago
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