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zordoloom
 2 years ago
Best ResponseYou've already chosen the best response.0Are you looking for exact or approximate answers?

akh14
 2 years ago
Best ResponseYou've already chosen the best response.0im not sure. it just says solve the following equation. i would guess exact

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{x^2}{3}  \frac{25}{49} = 0\] \[\frac{x^2}{3} = \frac{25}{49} = \frac{5^2}{7^2} = (\frac{5}{7})^2\] Can you solve that for x? Remember, there will be a negative and a positive root.

akh14
 2 years ago
Best ResponseYou've already chosen the best response.0im sorry i wrote it wrong the x^2/3 should be x^(2/3)

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0\[x^{2/3}  \frac{25}{49} = 0\] is the real problem?

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0That isn't too hard. Move the fraction to the right hand side, and then undo that gnarly exponent. Remember, \(x^{\frac{2}{3}} = \sqrt[3]{x^2}\).

akh14
 2 years ago
Best ResponseYou've already chosen the best response.0so now i have x^2= (25/49)^3

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0Yes. Take the square root of the right hand fraction before cubing it, that will be easier!

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0Do you have a final answer?

akh14
 2 years ago
Best ResponseYou've already chosen the best response.0no haha i have no idea why take the sqrrt of the right side
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