A local store owner pays her employees time-and-a-half for overtime. That means if an employee works more than 40 hours per week, the store will pay him 1.5 times his regular hourly wage of $6.50

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A local store owner pays her employees time-and-a-half for overtime. That means if an employee works more than 40 hours per week, the store will pay him 1.5 times his regular hourly wage of $6.50

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Write and graph a piecewise function that illustrates an employee's weekly pay, W, as a function of the number of hours, h, that employee works.
having some trouble with this, if somebody could explain how i could solve this i would really appreciate it!
f(x) = 6.50x, x <=40 f(x) = 260 + 9.75x, x > 40 Sorry, that's the best I can do.

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That's not really it, but it's close
thanks, i got this does this seem to make sense or is this wrong? P = {0 h<0 6.5 h 0≤h≤40 260+9.75 40
But you still need a variable for the the third interval.
The problem is, you need a variable that will represent h > 40 because it won't be the same as 0 < h < 40
for h > 40, it is overtime so it starts back at 1 again.
For instance, if she works one hour overtime, it won't be 260 + 9.75(41) it will be 260 + 9.75(1) For two hours, it will be 260 + 9.75(2) so the variable cannot be h. It has to be "o" maybe for overtime hours. But we have to write a piecewise function in terms of the same variable, so good luck with that.
I figured it out.
For the 3rd interval, you have to find the equation of the line. So use points (40, 260) and (41, 269.75) to find the slope, then re-write the equation of the line in terms of h.
oh okay thank you soo much, what would the equation be in that case?
wait
f(h) = 9.75h - 130
Tricky problem, but not impossible to figure out
so f(h) = 6.50h 0 < h < 40 f(h) = 9.75h - 130 h > 40
@Hero thank you so much, i understand much better now. do you know how i could graph that?
never mind i got it :)

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