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f(x) = 6.50x, x <=40
f(x) = 260 + 9.75x, x > 40
Sorry, that's the best I can do.

That's not really it, but it's close

thanks, i got this
does this seem to make sense or is this wrong?
P = {0 h<0
6.5 h 0≤h≤40
260+9.75 40

But you still need a variable for the the third interval.

for h > 40, it is overtime so it starts back at 1 again.

I figured it out.

oh okay thank you soo much, what would the equation be in that case?

wait

f(h) = 9.75h - 130

Tricky problem, but not impossible to figure out

so
f(h) = 6.50h 0 < h < 40
f(h) = 9.75h - 130 h > 40

never mind i got it :)