## anonymous 3 years ago how do I find the derivative of f(x)= sin[ln(cosx^3)]

1. ash2326

Use chain rule here $\frac{d}{dx} f( g(x))=f'(x)\times \frac{d}{dx} g(x)$ Could you try ?

2. anonymous

would it be cos[lncosx^3] X (-sinx^3)/(cosx^3) ?

3. ash2326

times the derivative of x^3 $\cos (\ln{\cos x^3})\times \frac{1}{\cos x^3}\times (-\sin x^3)\times \frac{d}{dx} (x^3)$ Good work btw

4. anonymous

Thanks !

5. ash2326

You're welcome :D