anonymous
  • anonymous
CHECK MY WORK
Mathematics
jamiebookeater
  • jamiebookeater
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nincompoop
  • nincompoop
correct!
anonymous
  • anonymous
|dw:1359436205915:dw|
anonymous
  • anonymous
Does that say x is less than 1?

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anonymous
  • anonymous
|dw:1359436614514:dw|
anonymous
  • anonymous
?
anonymous
  • anonymous
@jim_thompson5910
whpalmer4
  • whpalmer4
Are you saying that if \[\frac{(2x+1)}{(x+1)} \le 2\] then \[x \le 1\]?
anonymous
  • anonymous
so im right?
anonymous
  • anonymous
wait no my answer is x<1
nincompoop
  • nincompoop
show your step-by-step solution
whpalmer4
  • whpalmer4
How about if x = -2? (2(-2)+1)/(-2+1) = -3/-1 = 3, oops.
anonymous
  • anonymous
@whpalmer4 , no thats not a answer choice.
whpalmer4
  • whpalmer4
My point is that x = -2 is a value that should work if your answer is correct. It doesn't. Therefore, your answer is not correct.
anonymous
  • anonymous
so \[x \ge -1\]
nincompoop
  • nincompoop
SHOW YOUR SOLUTION :)
whpalmer4
  • whpalmer4
You're clearly just guessing at a list of answers. If you are going to do that, you need to check your guesses!

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