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kitsune0724
Group Title
Simplify:
1/(7x)1/(5x)
and
Find a solution: 1/9x+1/10=11/90
please and thank you.
 one year ago
 one year ago
kitsune0724 Group Title
Simplify: 1/(7x)1/(5x) and Find a solution: 1/9x+1/10=11/90 please and thank you.
 one year ago
 one year ago

This Question is Closed

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{1}{7x}\frac{1}{5x}\]Find a common denominator, then combine. Do you know how to do that?
 one year ago

kitsune0724 Group TitleBest ResponseYou've already chosen the best response.0
I think so. Thank you.
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
For the other one, the same approach is appropriate. Find a common denominator, or multiply the whole equation by the product of all of the denominators.
 one year ago

kitsune0724 Group TitleBest ResponseYou've already chosen the best response.0
is it 2/35?
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
There better be an x in there somewhere, don't you think?
 one year ago

kitsune0724 Group TitleBest ResponseYou've already chosen the best response.0
Yes there is. Thank you again.
 one year ago

some_someone Group TitleBest ResponseYou've already chosen the best response.1
(1)/(7x)(1)/(5x) To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 35x. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. (1)/(7x)*(5)/(5)(1)/(5x)*(7)/(7) Multiply 1 by 5 to get 5. (5)/(5*7x)(1)/(5x)*(7)/(7) Multiply 7x by 5 to get 35x. (5)/(35x)(1)/(5x)*(7)/(7) Multiply 1 by 7 to get 7. (5)/(35x)(7)/(7*5x) Multiply 5x by 7 to get 35x. (5)/(35x)(7)/(35x) Combine the numerators of all expressions that have common denominators. (57)/(35x) Subtract 7 from 5 to get 2. (2)/(35x) Move the minus sign from the numerator to the front of the expression. 2/35x
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
Agree with 2/35x.
 one year ago

some_someone Group TitleBest ResponseYou've already chosen the best response.1
(1)/(9)*x+(1)/(10)=(11)/(90) Multiply 1 by x to get x. (x)/(9)+(1)/(10)=(11)/(90) Since (1)/(10) does not contain the variable to solve for, move it to the righthand side of the equation by subtracting (1)/(10) from both sides. (x)/(9)=(1)/(10)+(11)/(90) To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 90. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. (x)/(9)=(11)/(90)(1)/(10)*(9)/(9) Multiply 1 by 9 to get 9. (x)/(9)=(11)/(90)(9)/(9*10) Multiply 10 by 9 to get 90. (x)/(9)=(11)/(90)(9)/(90) Combine the numerators of all fractions that have common denominators. (x)/(9)=(119)/(90) Subtract 9 from 11 to get 2. (x)/(9)=(2)/(90) Cancel the common factor of 2 the expression (2)/(90). (x)/(9)=(<X>2<x>)/(45<X>90<x>) Remove the common factors that were cancelled out. (x)/(9)=(1)/(45) Multiply each term in the equation by 9. (x)/(9)*9=(1)/(45)*9 Cancel the common factor of 9 in the denominator of the first term (x)/(9) and the second term 9. (x)/(<X>9<x>)*<X>9<x>=(1)/(45)*9 Reduce the expression by removing the common factor of 9 in the denominator of the first term (x)/(9) and the second term 9. x*1=(1)/(45)*9 Multiply x by 1 to get x. x=(1)/(45)*9 Cancel the common factor of 9 in the denominator of the first term (1)/(45) and the second term 9. x=(1)/(5<X>45<x>)*<X>9<x> Reduce the expression by removing the common factor of 9 in the denominator of the first term (1)/(45) and the second term 9. x=(1)/(5)*1 Multiply 1 by 1 to get 1. x=(1)/(5)
 one year ago

kitsune0724 Group TitleBest ResponseYou've already chosen the best response.0
can you please draw it for me? Thank you.
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
Is the problem \[\frac{1}{9x} + ... \] or \[\frac{1}{9}x + ...\]?
 one year ago

kitsune0724 Group TitleBest ResponseYou've already chosen the best response.0
dw:1359439362873:dw this is the problem.
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{1}{9}x + \frac{1}{10} = \frac{11}{90}\] Okay, what should we use as a common denominator?
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
As 9 and 10 are both factors of 90, I'll take 90 as the common denominator. I'll multiply the first term by 10/10, the second term by 9/9. \[\frac{10}{10}*\frac{1}{9}x + \frac{9}{9}*\frac{1}{10} = \frac{11}{90}\] \[\frac{10x}{90} + \frac{9}{90} = \frac{11}{90}\]Now subtract 9/90 from both sides and solve for x.
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
Alternatively, I would have multiplied everything by 90 to eliminate the fractions from the outset, but it's good to get some practice working with fractions!
 one year ago

kitsune0724 Group TitleBest ResponseYou've already chosen the best response.0
Would it be 9/10?
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{10x}{90} + \frac{9}{90}  \frac{9}{90} = \frac{11}{90}  \frac{9}{90}\] \[\frac{10x}{90} = \frac{119}{90}\]
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{10x}{90} = \frac{119}{90} = \frac{2}{90}\]Okay, what does x equal?
 one year ago
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