anonymous
  • anonymous
Simplify: 1/(7x)-1/(5x) and Find a solution: 1/9x+1/10=11/90 please and thank you.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
whpalmer4
  • whpalmer4
\[\frac{1}{7x}-\frac{1}{5x}\]Find a common denominator, then combine. Do you know how to do that?
anonymous
  • anonymous
I think so. Thank you.
whpalmer4
  • whpalmer4
For the other one, the same approach is appropriate. Find a common denominator, or multiply the whole equation by the product of all of the denominators.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
is it 2/35?
whpalmer4
  • whpalmer4
There better be an x in there somewhere, don't you think?
anonymous
  • anonymous
Yes there is. Thank you again.
anonymous
  • anonymous
(1)/(7x)-(1)/(5x) To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 35x. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. (1)/(7x)*(5)/(5)-(1)/(5x)*(7)/(7) Multiply 1 by 5 to get 5. (5)/(5*7x)-(1)/(5x)*(7)/(7) Multiply 7x by 5 to get 35x. (5)/(35x)-(1)/(5x)*(7)/(7) Multiply -1 by 7 to get -7. (5)/(35x)-(7)/(7*5x) Multiply 5x by 7 to get 35x. (5)/(35x)-(7)/(35x) Combine the numerators of all expressions that have common denominators. (5-7)/(35x) Subtract 7 from 5 to get -2. (-2)/(35x) Move the minus sign from the numerator to the front of the expression. -2/35x
whpalmer4
  • whpalmer4
Agree with -2/35x.
anonymous
  • anonymous
(1)/(9)*x+(1)/(10)=(11)/(90) Multiply 1 by x to get x. (x)/(9)+(1)/(10)=(11)/(90) Since (1)/(10) does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting (1)/(10) from both sides. (x)/(9)=-(1)/(10)+(11)/(90) To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 90. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. (x)/(9)=(11)/(90)-(1)/(10)*(9)/(9) Multiply -1 by 9 to get -9. (x)/(9)=(11)/(90)-(9)/(9*10) Multiply 10 by 9 to get 90. (x)/(9)=(11)/(90)-(9)/(90) Combine the numerators of all fractions that have common denominators. (x)/(9)=(11-9)/(90) Subtract 9 from 11 to get 2. (x)/(9)=(2)/(90) Cancel the common factor of 2 the expression (2)/(90). (x)/(9)=(2)/(4590) Remove the common factors that were cancelled out. (x)/(9)=(1)/(45) Multiply each term in the equation by 9. (x)/(9)*9=(1)/(45)*9 Cancel the common factor of 9 in the denominator of the first term (x)/(9) and the second term 9. (x)/(9)*9=(1)/(45)*9 Reduce the expression by removing the common factor of 9 in the denominator of the first term (x)/(9) and the second term 9. x*1=(1)/(45)*9 Multiply x by 1 to get x. x=(1)/(45)*9 Cancel the common factor of 9 in the denominator of the first term (1)/(45) and the second term 9. x=(1)/(545)*9Reduce the expression by removing the common factor of 9 in the denominator of the first term (1)/(45) and the second term 9. x=(1)/(5)*1 Multiply 1 by 1 to get 1. x=(1)/(5)
anonymous
  • anonymous
can you please draw it for me? Thank you.
whpalmer4
  • whpalmer4
Is the problem \[\frac{1}{9x} + ... \] or \[\frac{1}{9}x + ...\]?
anonymous
  • anonymous
|dw:1359439362873:dw| this is the problem.
whpalmer4
  • whpalmer4
\[\frac{1}{9}x + \frac{1}{10} = \frac{11}{90}\] Okay, what should we use as a common denominator?
whpalmer4
  • whpalmer4
As 9 and 10 are both factors of 90, I'll take 90 as the common denominator. I'll multiply the first term by 10/10, the second term by 9/9. \[\frac{10}{10}*\frac{1}{9}x + \frac{9}{9}*\frac{1}{10} = \frac{11}{90}\] \[\frac{10x}{90} + \frac{9}{90} = \frac{11}{90}\]Now subtract 9/90 from both sides and solve for x.
whpalmer4
  • whpalmer4
Alternatively, I would have multiplied everything by 90 to eliminate the fractions from the outset, but it's good to get some practice working with fractions!
anonymous
  • anonymous
Would it be 9/10?
whpalmer4
  • whpalmer4
\[\frac{10x}{90} + \frac{9}{90} - \frac{9}{90} = \frac{11}{90} - \frac{9}{90}\] \[\frac{10x}{90} = \frac{11-9}{90}\]
anonymous
  • anonymous
2/90
whpalmer4
  • whpalmer4
\[\frac{10x}{90} = \frac{11-9}{90} = \frac{2}{90}\]Okay, what does x equal?

Looking for something else?

Not the answer you are looking for? Search for more explanations.