• eujc21
The May 1, 2009 issue of The Montclarian reported the fol- lowing home sale amounts for a sample of homes in Alameda, CA that were sold the previous month (1000s of $): 590 815 575 608 350 1285 408 540 555 679 a. Calculate and interpret the sample mean and median. b. Suppose the 6th observation had been 985 rather than 1285. How would the mean and median change? c. Calculate a 20% trimmed mean by first trimming the two smallest and two largest observations. d. Calculate a 15% trimmed mean.
  • schrodinger
See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this
and thousands of other questions

  • kropot72
a. To calculate the sample mean, add the 10 amounts and divide the total by 10. To find the median, rank the amounts in ascending order (lowest amount first). Since there is an even number of data the median is found by taking the arithmetic mean of the fifth and sixth amounts.
  • eujc21

Looking for something else?

Not the answer you are looking for? Search for more explanations.