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1) Find the zeros of f(x)=(x4)^4(x+5)^6 and state the multiplicity.
2) Find the zeros of f(x)=(x3)^2(x5)^2 and state the multiplicity.
~My answers~
4, multiplicity 4; –5, multiplicity 6
2, multiplicity 3; 2, multiplicity 5
 one year ago
 one year ago
1) Find the zeros of f(x)=(x4)^4(x+5)^6 and state the multiplicity. 2) Find the zeros of f(x)=(x3)^2(x5)^2 and state the multiplicity. ~My answers~ 4, multiplicity 4; –5, multiplicity 6 2, multiplicity 3; 2, multiplicity 5
 one year ago
 one year ago

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AzteckBest ResponseYou've already chosen the best response.1
You mixed up the answers for question 2. Reread your answers for question 2.
 one year ago

Kagome_gurl8Best ResponseYou've already chosen the best response.0
wait so it'd be 3, multiplicity 2; 5, multiplicity 2? @Azteck
 one year ago

AzteckBest ResponseYou've already chosen the best response.1
Go by what you did in question 1. If what you wrote just now matches what you did in question 1, then you know it's correct.
 one year ago

Kagome_gurl8Best ResponseYou've already chosen the best response.0
I am very confused...
 one year ago

TimSmitBest ResponseYou've already chosen the best response.1
Your new answer is correct, you switched the zeroes and the multiplicity for question 2 in your original answer.
 one year ago

Kagome_gurl8Best ResponseYou've already chosen the best response.0
So they are both correct now? @TimSmit
 one year ago

AzteckBest ResponseYou've already chosen the best response.1
Dude, be confident of what you put. Being dependent on us strangers rather than feeling that the answer is correct means you're not confident at all.
 one year ago

AzteckBest ResponseYou've already chosen the best response.1
of what you put as the answer*
 one year ago

TimSmitBest ResponseYou've already chosen the best response.1
They are correct :) but as azteck says, you came close to the solution yourself which shows you understand, but mixed two numbers, it happens.
 one year ago

Kagome_gurl8Best ResponseYou've already chosen the best response.0
:) Thank you for pointing it out.
 one year ago
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