anonymous
  • anonymous
1) Find the zeros of f(x)=(x-4)^4(x+5)^6 and state the multiplicity. 2) Find the zeros of f(x)=(x-3)^2(x-5)^2 and state the multiplicity. ~My answers~ 4, multiplicity 4; –5, multiplicity 6 2, multiplicity 3; 2, multiplicity 5
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
are these right?
anonymous
  • anonymous
You mixed up the answers for question 2. Re-read your answers for question 2.
anonymous
  • anonymous
wait so it'd be 3, multiplicity 2; 5, multiplicity 2? @Azteck

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Go by what you did in question 1. If what you wrote just now matches what you did in question 1, then you know it's correct.
anonymous
  • anonymous
I am very confused...
anonymous
  • anonymous
Your new answer is correct, you switched the zeroes and the multiplicity for question 2 in your original answer.
anonymous
  • anonymous
So they are both correct now? @TimSmit
anonymous
  • anonymous
Dude, be confident of what you put. Being dependent on us strangers rather than feeling that the answer is correct means you're not confident at all.
anonymous
  • anonymous
of what you put as the answer*
anonymous
  • anonymous
oh...okay....
anonymous
  • anonymous
They are correct :) but as azteck says, you came close to the solution yourself which shows you understand, but mixed two numbers, it happens.
anonymous
  • anonymous
:) Thank you for pointing it out.

Looking for something else?

Not the answer you are looking for? Search for more explanations.