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TeemoTheTerific
 3 years ago
HELP PLEASE!!!
Im stuck on how to start(and finish)
TeemoTheTerific
 3 years ago
HELP PLEASE!!! Im stuck on how to start(and finish)

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TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0If \[\huge(3x ^{n})^{3} \times (3x)^{n6}= ax ^{2}\] Find the value of n AND a

Azteck
 3 years ago
Best ResponseYou've already chosen the best response.0\[\large (ax^n)^2=ax^{2n}\]

Azteck
 3 years ago
Best ResponseYou've already chosen the best response.0Use that property. Also use this \[\large 2x^n \times 2x^{n1}=2x^{n+(n1)}\]

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0how would that help when it is 3x not 2x

theanonymous27
 3 years ago
Best ResponseYou've already chosen the best response.0do u play LoL with teemo? hehe

Azteck
 3 years ago
Best ResponseYou've already chosen the best response.0\[\large ax^n \times ax^{n1}=ax^{n+(n1)}\]

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0i really dont understand hows that gonna help

Azteck
 3 years ago
Best ResponseYou've already chosen the best response.0Wait I think it's a^2 as the result not just a.

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2look at the 1st part this requires the power of a power law \[(ax^n)^m = a^m x^{n \times m}\] the outer power operates on the constant a as well as x^n use this to simplify \[(3x^n)^3\]

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2thats correct... but for this question I'd leave it as 3^3 apply the same rule to the 2nd term... \[(3x)^{n 6}\]

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2correct... so do you know about adding powers when mutiplying the same base..? because you have \[3^3x^{3n} \times 3^{n  6} x^{n  6} = 3^3 \times 3^{n  6} \times x^{3n} \times x^{n  6}\]

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0yea i think i can do that

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0where did the a go?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2you said you can do it.. use the law \[m^a \times m^b = m^{a +b}\]

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2but this applies to same base...

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0\[\huge3^3x^{3n} \times 3^{n  6} x^{n  6} = 3^3 \times 3^{n  6} \times x^{3n} \times x^{n  6}\] this is it right?

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0derp it cut the 6 out :P

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2well you just need to finish it

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0im really confused where did the ax^2 went

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2don't worry about ax^2.. all you need to do is simplify the right side of your previous posting \[3^{3 + n  6} \times x^{3n + n  6} = \]

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0\[\huge3^{n  3} \times x^{4n  6} \]

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2yep... just write your answer without the multiplication sign

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0\[\huge3^{n  3} x^{4n  6}\]

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2thats a correct solution

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0mhm not sure if that helps lol

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2ok... so lets look at the power of x 4n  6 = 2 solve for n....

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0then we plug x into the equation?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2not x... n = 2 so you have all you need to do is evaluate \[3^{n  3}\] when n = 2 to find a

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2does that make sense... when you equate the powers of x... you have \[x^{4n  6} = x^2\] so 4n  6 = 2 so n = 2 use this for the powers of 3 3\[3^{2  3} = 3^{1}.... or..... \frac{1}{3} \] so a = 1/3

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0ahh ok :) thanks for putting up with me :)

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.2glad to help... lots of index laws in simplifying before you can solve for n and a

TeemoTheTerific
 3 years ago
Best ResponseYou've already chosen the best response.0your my fave maths teach lol well so far...
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