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TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0If \[\huge(3x ^{n})^{3} \times (3x)^{n6}= ax ^{2}\] Find the value of n AND a

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0\[\large (ax^n)^2=ax^{2n}\]

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0Use that property. Also use this \[\large 2x^n \times 2x^{n1}=2x^{n+(n1)}\]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0how would that help when it is 3x not 2x

theanonymous27
 one year ago
Best ResponseYou've already chosen the best response.0do u play LoL with teemo? hehe

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0\[\large ax^n \times ax^{n1}=ax^{n+(n1)}\]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0i really dont understand hows that gonna help

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0Wait I think it's a^2 as the result not just a.

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2look at the 1st part this requires the power of a power law \[(ax^n)^m = a^m x^{n \times m}\] the outer power operates on the constant a as well as x^n use this to simplify \[(3x^n)^3\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2thats correct... but for this question I'd leave it as 3^3 apply the same rule to the 2nd term... \[(3x)^{n 6}\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2correct... so do you know about adding powers when mutiplying the same base..? because you have \[3^3x^{3n} \times 3^{n  6} x^{n  6} = 3^3 \times 3^{n  6} \times x^{3n} \times x^{n  6}\]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0yea i think i can do that

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0where did the a go?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2you said you can do it.. use the law \[m^a \times m^b = m^{a +b}\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2but this applies to same base...

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge3^3x^{3n} \times 3^{n  6} x^{n  6} = 3^3 \times 3^{n  6} \times x^{3n} \times x^{n  6}\] this is it right?

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0derp it cut the 6 out :P

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2well you just need to finish it

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0im really confused where did the ax^2 went

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2don't worry about ax^2.. all you need to do is simplify the right side of your previous posting \[3^{3 + n  6} \times x^{3n + n  6} = \]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge3^{n  3} \times x^{4n  6} \]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2yep... just write your answer without the multiplication sign

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge3^{n  3} x^{4n  6}\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2thats a correct solution

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0mhm not sure if that helps lol

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2ok... so lets look at the power of x 4n  6 = 2 solve for n....

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0then we plug x into the equation?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2not x... n = 2 so you have all you need to do is evaluate \[3^{n  3}\] when n = 2 to find a

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2does that make sense... when you equate the powers of x... you have \[x^{4n  6} = x^2\] so 4n  6 = 2 so n = 2 use this for the powers of 3 3\[3^{2  3} = 3^{1}.... or..... \frac{1}{3} \] so a = 1/3

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0ahh ok :) thanks for putting up with me :)

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2glad to help... lots of index laws in simplifying before you can solve for n and a

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0your my fave maths teach lol well so far...
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