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TeemoTheTerificBest ResponseYou've already chosen the best response.0
If \[\huge(3x ^{n})^{3} \times (3x)^{n6}= ax ^{2}\] Find the value of n AND a
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
\[\large (ax^n)^2=ax^{2n}\]
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
Use that property. Also use this \[\large 2x^n \times 2x^{n1}=2x^{n+(n1)}\]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
how would that help when it is 3x not 2x
 one year ago

theanonymous27Best ResponseYou've already chosen the best response.0
do u play LoL with teemo? hehe
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
\[\large ax^n \times ax^{n1}=ax^{n+(n1)}\]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
i really dont understand hows that gonna help
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
Wait I think it's a^2 as the result not just a.
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
look at the 1st part this requires the power of a power law \[(ax^n)^m = a^m x^{n \times m}\] the outer power operates on the constant a as well as x^n use this to simplify \[(3x^n)^3\]
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
thats correct... but for this question I'd leave it as 3^3 apply the same rule to the 2nd term... \[(3x)^{n 6}\]
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
correct... so do you know about adding powers when mutiplying the same base..? because you have \[3^3x^{3n} \times 3^{n  6} x^{n  6} = 3^3 \times 3^{n  6} \times x^{3n} \times x^{n  6}\]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
yea i think i can do that
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
where did the a go?
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
you said you can do it.. use the law \[m^a \times m^b = m^{a +b}\]
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
but this applies to same base...
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
\[\huge3^3x^{3n} \times 3^{n  6} x^{n  6} = 3^3 \times 3^{n  6} \times x^{3n} \times x^{n  6}\] this is it right?
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
derp it cut the 6 out :P
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
well you just need to finish it
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
im really confused where did the ax^2 went
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
don't worry about ax^2.. all you need to do is simplify the right side of your previous posting \[3^{3 + n  6} \times x^{3n + n  6} = \]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
\[\huge3^{n  3} \times x^{4n  6} \]
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
yep... just write your answer without the multiplication sign
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
\[\huge3^{n  3} x^{4n  6}\]
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
thats a correct solution
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
mhm not sure if that helps lol
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
ok... so lets look at the power of x 4n  6 = 2 solve for n....
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
then we plug x into the equation?
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
not x... n = 2 so you have all you need to do is evaluate \[3^{n  3}\] when n = 2 to find a
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
does that make sense... when you equate the powers of x... you have \[x^{4n  6} = x^2\] so 4n  6 = 2 so n = 2 use this for the powers of 3 3\[3^{2  3} = 3^{1}.... or..... \frac{1}{3} \] so a = 1/3
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
ahh ok :) thanks for putting up with me :)
 one year ago

campbell_stBest ResponseYou've already chosen the best response.2
glad to help... lots of index laws in simplifying before you can solve for n and a
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.0
your my fave maths teach lol well so far...
 one year ago
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