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Find the value of x on a right triangle when 2 variables are missing and the hypotenuse is 3 square root of 2

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|dw:1359443877815:dw|for a better look at the problem
|dw:1359444180420:dw| Since BC=AC and
|dw:1359444336807:dw| sin45=opp/hyp 1/(sqrt2)=x/(3sqrt2) Can u find x nw? @Suleman_Ahmed

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Other answers:

I'm still confused can you do it step by step and the answer has to be radical form.
|dw:1359444635517:dw| Since BC=AC and
ok good:)
Are u familiar with trigonometirc identities like cos, sin, tan etc?
Actually I'm not, sorry.
k. hw abt pythagoras' theorem?
yes I know that.
hmm good.:) so use that to find x. Can u do?
I'm very new to this so i don't think i can.
Can u plz tell me vat is pythagoras' theorem?
a squared + b squared = c squared
Nw from ur diagram can u tell me vat is a, b and c?
A=45 B=45 C=90
|dw:1359445451467:dw| In ur diagram a=x, b=x and c=3sqrt2 Following it?
yes now I am
Nw can u find x using the puthagoras' theorem?
a squared ?
okay i understand a little better
Can u find x nw? @Suleman_Ahmed
what is x^2+x^2=?
3sqr root 2
x^2+x^2=2x^2 2x^2=(3sqrt2)^2 (3sqrt2)^2=3^2*(sqrt2)^2 =9*2 Hope that helps.
okay thanks that did

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