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NotTimBest ResponseYou've already chosen the best response.0
so where would the 45 degree angle go i nthe triangle?
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
i never did get it right
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
dw:1359448218371:dw
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
dw:1359419770094:dw @shubhamsrg ?
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
45 will be special case where all angles be 45 Leme explain you a general case, with angle = x
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
dw:1359448684677:dw
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
dw:1359448743336:dw
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
Hint: Except in geometrical solving of problems, NEVER EVER draw general diagrams with 45° angles. Always draw 20° to 30° angles. It will save you a lot of time.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
dw:1359448787878:dw
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
dw:1359448817064:dw
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
dw:1359448798875:dw
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
dw:1359420708200:dw So I know what is going on, then this would be correct also?
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
dw:1359449644111:dw WHere does this direction point to? If it is horizontal, then you are wrong again. "Your" angle is the other one.
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
@VincentLyon.Fr how do you get that?
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
just remember when parallel to the slope means: Force produced by the weight> mgsinx if its perpendicular ( normal ) to the slope, use mgcosx
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
the main slope, or the new, smaller slope?
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
the original one, below the slope, angle use 45 degrees
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
dw:1359455671403:dw For x axis : is always sine For y axis : is always cosine
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
wait. sorry, so hwo can i derive where the angle will be?
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
just use this angle for both axisdw:1359458196671:dw
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
wait...so how do i know the angle for the hypothetical top triangle?
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
dw:1359460336556:dw
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
Ok. To anyone else answering, I will be leaving within 5 minutes. Thamks for all the help guys! At the very least, I know where the angles go, even if I do not knw how to derive it.
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
you have to know your trigonometry well and have to look at different angles to solve this problem
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
dw:1359461884908:dw For the force directed on x axis due to resultant force, F on x = Fcos(30) For the force directed on y axis due to resultant force, F on y = Fsin(30)
 one year ago

CalculatorBest ResponseYou've already chosen the best response.0
dw:1359462169659:dw
 one year ago
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