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so where would the 45 degree angle go i nthe triangle?

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i never did get it right
This should help ?
|dw:1359419770094:dw| @shubhamsrg ?
45 will be special case where all angles be 45 Leme explain you a general case, with angle = x
say it wasn't 45...
Hint: Except in geometrical solving of problems, NEVER EVER draw general diagrams with 45° angles. Always draw 20° to 30° angles. It will save you a lot of time.
|dw:1359420708200:dw| So I know what is going on, then this would be correct also?
|dw:1359449644111:dw| WHere does this direction point to? If it is horizontal, then you are wrong again. "Your" angle is the other one.
@Vincent-Lyon.Fr how do you get that?
just remember when parallel to the slope means: Force produced by the weight-> mgsinx if its perpendicular ( normal ) to the slope, use mgcosx
the main slope, or the new, smaller slope?
the original one, below the slope, angle use 45 degrees
|dw:1359455671403:dw| For x axis : is always sine For y axis : is always cosine
wait. sorry, so hwo can i derive where the angle will be?
  • tcy
just use this angle for both axis|dw:1359458196671:dw| how do i know the angle for the hypothetical top triangle?
Ok. To anyone else answering, I will be leaving within 5 minutes. Thamks for all the help guys! At the very least, I know where the angles go, even if I do not knw how to derive it.
you have to know your trigonometry well and have to look at different angles to solve this problem
|dw:1359461884908:dw| For the force directed on x axis due to resultant force, F on x = Fcos(30) For the force directed on y axis due to resultant force, F on y = Fsin(30)

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