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cozyfire

  • one year ago

In an experiment' the population P of bacteria in t hours is given by P=1000e^kt,where k is constant. If the size of the population of bacteria is found to be 3000 after 10 hours, what is the size of the population after 5 hours?

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  1. AravindG
    • one year ago
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    first of all : \[\huge \color{green}{\text{WELCOME TO OPENSTUDY!}}\]

  2. donimic4
    • one year ago
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    lol

  3. AravindG
    • one year ago
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    ok now to your question: first use the given information to get value of k

  4. AravindG
    • one year ago
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    @cozyfire just use the equation and substitute values

  5. AravindG
    • one year ago
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    k is the unknown

  6. cozyfire
    • one year ago
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    umm k=0.109861228 what's next??

  7. AravindG
    • one year ago
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    if you get the value of k use the equation again to get P .

  8. AravindG
    • one year ago
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    because with k known p is thee only unknown in the second part of question

  9. cozyfire
    • one year ago
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    what i don't understand is how will you eliminate e using the calculator?? sorry we haven't discussed this yet it's our assignment to figure it out

  10. AravindG
    • one year ago
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    eliminate e ? then how did you get k value?

  11. AravindG
    • one year ago
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    in btw the k value you reported is correct as well as accurate :)

  12. cozyfire
    • one year ago
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    well i kinda followed some equation and just substituted the values but if i will solve this i will get In(P/1000)=5k i don't know what to do next

  13. AravindG
    • one year ago
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    well lets look at second part then

  14. AravindG
    • one year ago
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    you got k value as .109 Now \[\large P=1000 e^{0.109 \times 10}\]

  15. AravindG
    • one year ago
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    e approx value is 2.718

  16. AravindG
    • one year ago
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    can you do it now?

  17. AravindG
    • one year ago
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    oops one correction its 5 not 10

  18. cozyfire
    • one year ago
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    yup thank u very much!!

  19. AravindG
    • one year ago
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    yw :)

  20. donimic4
    • one year ago
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    Your welcome :) lol jk

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