## anonymous 3 years ago /

1. anonymous

you might want to simplify that radical before you start. $$\frac{x^3}{x^{-4}}=x^7$$

2. anonymous

|dw:1359462487555:dw|

3. anonymous

$x^{3}\div x ^{-4} = x^{7}$ \$∫x^{7}dx = \left[ x^{8} \div 8 \right] + c$ c is a constant.. Hope this helps..