separate y on LHS you will get what you want
to get the y intercept substitute the values of x with 0
to get the slope y=mx+c so you need to transform the equation
m is the slope
3x-2y+8=0 2y=3x+8 divide the whole equation to 2 u will get y=3/2(x)+4 so the slope is 3/2
ok so once i get the y intercept why do i divide it by 2?
you can go about moving everything around; or, you can just determine the slope and y intercept in 3 moves. 1: y int is the value of y when x=0 2: the slope is the change in y when x changes by 1; so find the value of y when x=1 3: subtract the value when x=0 from the value when x=1 and you have your slope
as i told you just separate y on LHS you will get y = 3/2x+4 now compare it with y=mx+b to get slope and y-intercept here b= y-intercept and m = slope do it now
what does LHS mean?
left hand side
now what you got??
im not sure. and where the 8 go?
3x – 2y + 8 = 0. subtract 8 from both sides what you get???
now subtract 3x from both sides what you get??
why substract i thought you you add it? but 2y=-8-3x?
because 3x on left side has positive sign to cancel it out you have to subtract 3x on both sides
-2y=-8-3x now divide both sides by -2
no its y = 4+3/2x
oh ok is that the asnwer or is there more to it?
no you have to do one step now you have a general equation for line in slope intercept form that is y = mx+b here m = slope and b = y intercept can you find the slope and y-intercept now from y = 4+3/2x
now m =?? b= ???
these are respective values for slope and y-intercept
ok and that's it?
thank you now i understand it
you are welcome