anonymous
  • anonymous
Can somedbody help me with problem 3F-8, (b)? I can't understand the answer given...
MIT 18.01 Single Variable Calculus (OCW)
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
NoelGreco
  • NoelGreco
There are several somebodies out here who would be glad to help if you included a link to the problem itself.
anonymous
  • anonymous
Sure, sorry about that: the problem is in this pdf file
Stacey
  • Stacey
|dw:1359705070117:dw| Basically we end up with OB=y and AQ=x

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Stacey
  • Stacey
The point O is (0, 2y) and the point Q is (2x, 0), giving the slope of the line to be -y/x.
anonymous
  • anonymous
Thank you very much for your answer. I still don't know if I got it, though. What I understood from the problem is that I should find a curve such that for whatever point P in the curve that I chose, if I took the tangent at that point, P would be at exactly the midpoint of the segment of that line that lies in the first quadrant. But looking at your curve, and the one from the solution given, it seems to me that if I move up (down), the upper part of the line would be shorter (longer) than the lower part. Did I get the question wrong? Thank you!
Stacey
  • Stacey
|dw:1359951384469:dw| You seem to understand the problem correctly. The upper portion of my curve is definitely off, but I did manage to show a tangent for the lower section that should illustrate the concept.
Stacey
  • Stacey
|dw:1359952181692:dw| This graph might illustrate it better.
anonymous
  • anonymous
Thank you very much

Looking for something else?

Not the answer you are looking for? Search for more explanations.