arkababu
give the iupac name of



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arkababu
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dw:1359470162256:dw

shubhamsrg
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I do not understand your compound ?

arkababu
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u just have to do the nomenclature

arkababu
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is it (4proyl 6 etyl(1methyl)7(1chloromethyl)8(1methyl)3nonanol)

aaronq
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theres no hydroxide, so it can't have an ol ending.

aaronq
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the ending would be "ene" b/c of the double bond

shubhamsrg
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Its a bit complicated, hmm

aaronq
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on C6 it's isopropyl

shubhamsrg
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Can you tell me if halogen has higher precedence or double bond?

aaronq
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the double bond has higher precedence

shubhamsrg
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I guess that doesn't matter here hmm, You'll start numbering from left only and go just straight, right ?

aaronq
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you name them alphabetically

shubhamsrg
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dw:1359474124360:dw

aaronq
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nope the longest chain is 9 carbons

arkababu
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dw:1359474240821:dw

shubhamsrg
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but by going through the longest chain, we'll have to avoid halogen, are we allowed to do that ?

aaronq
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yep, chloromethyl

arkababu
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then there is hydroxide so is my answer right

arkababu
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is it (4proyl 6 etyl(1methyl)7(1chloromethyl)8(1methyl)3nonanol)

aaronq
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so you'll have to include the hydroxide in the main chain, which will not be the longest chain possible

aaronq
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3hydroxy6,7diisopropyl4propylnonan5ene

aaronq
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sorry it's "non5ene"

Frostbite
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Hmm I want it to be 7(chloromethyl)isopropyl8propylnon4en3ol

aaronq
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ah i missed the chloromethyl. but yeah that ending sounds good too, i'm not sure which one is "more" correct by iupac

Frostbite
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Yea.... think we need THE GOLDEN BOOK! (i hate it)

aaronq
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haha (Y)

Frostbite
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You wanna check it or do I? ;/

aaronq
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haha it doesn't matter, i'm just waiting for lecture to start so maybe the person who asked the question can check it out?