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boomerang285

  • 2 years ago

Just need some homework help please. Find the polar for of the following complex number: sqrt3 - sqrt3i. I believe the answer is 3(cos pi/4 + i sin pi/4), am I correct?

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  1. satellite73
    • 2 years ago
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    |dw:1359476827595:dw|

  2. satellite73
    • 2 years ago
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    angle should be either \(-\frac{\pi}{4}\) or \(\frac{7\pi}{4}\)

  3. satellite73
    • 2 years ago
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    absolute value is \[\sqrt{\sqrt{3}^2+\sqrt{3}^2}\] \[=\sqrt{3+3}=\sqrt{6}\]

  4. boomerang285
    • 2 years ago
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    the other answer options I have are 6(cos 7pi/4 + i sin 7pi/4) sqrt6(cos 7pi/4 - i sin 7pi/4) and sqrt6(cos 7pi/4 + i sin 7pi/4) I thought I worked it out correctly, guess not.

  5. satellite73
    • 2 years ago
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    it is the last one

  6. satellite73
    • 2 years ago
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    it helps to know what quadrant you are in so you can find the angle more easily \(\frac{\pi}{4}\) would put you in quadrant 1 but you are in quadrant 4

  7. boomerang285
    • 2 years ago
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    Yes, after seeing what you wrote I guess so. Thank you for that.

  8. satellite73
    • 2 years ago
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    yw oh and don't forget \(|a+bi|=\sqrt{a^2+b^2}\)

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