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## boomerang285 3 years ago Just need some homework help please. Find the polar for of the following complex number: sqrt3 - sqrt3i. I believe the answer is 3(cos pi/4 + i sin pi/4), am I correct?

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1. satellite73

|dw:1359476827595:dw|

2. satellite73

angle should be either $$-\frac{\pi}{4}$$ or $$\frac{7\pi}{4}$$

3. satellite73

absolute value is $\sqrt{\sqrt{3}^2+\sqrt{3}^2}$ $=\sqrt{3+3}=\sqrt{6}$

4. boomerang285

the other answer options I have are 6(cos 7pi/4 + i sin 7pi/4) sqrt6(cos 7pi/4 - i sin 7pi/4) and sqrt6(cos 7pi/4 + i sin 7pi/4) I thought I worked it out correctly, guess not.

5. satellite73

it is the last one

6. satellite73

it helps to know what quadrant you are in so you can find the angle more easily $$\frac{\pi}{4}$$ would put you in quadrant 1 but you are in quadrant 4

7. boomerang285

Yes, after seeing what you wrote I guess so. Thank you for that.

8. satellite73

yw oh and don't forget $$|a+bi|=\sqrt{a^2+b^2}$$

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