## boomerang285 Group Title Just need some homework help please. Find the polar for of the following complex number: sqrt3 - sqrt3i. I believe the answer is 3(cos pi/4 + i sin pi/4), am I correct? one year ago one year ago

1. satellite73 Group Title

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2. satellite73 Group Title

angle should be either $$-\frac{\pi}{4}$$ or $$\frac{7\pi}{4}$$

3. satellite73 Group Title

absolute value is $\sqrt{\sqrt{3}^2+\sqrt{3}^2}$ $=\sqrt{3+3}=\sqrt{6}$

4. boomerang285 Group Title

the other answer options I have are 6(cos 7pi/4 + i sin 7pi/4) sqrt6(cos 7pi/4 - i sin 7pi/4) and sqrt6(cos 7pi/4 + i sin 7pi/4) I thought I worked it out correctly, guess not.

5. satellite73 Group Title

it is the last one

6. satellite73 Group Title

it helps to know what quadrant you are in so you can find the angle more easily $$\frac{\pi}{4}$$ would put you in quadrant 1 but you are in quadrant 4

7. boomerang285 Group Title

Yes, after seeing what you wrote I guess so. Thank you for that.

8. satellite73 Group Title

yw oh and don't forget $$|a+bi|=\sqrt{a^2+b^2}$$