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darkb0nebeauty

Ultraviolent rays, which cause sun burn by penetrating only the top level of kin, have a wavelength about 1000 times the wavelength of an X-ray. Find the wavelength of ultraviolent rays. Show your work.

  • one year ago
  • one year ago

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  1. darkb0nebeauty
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    Medical X-rays, with a wavelength of about 10 ^-10m, can penetrate completely through you skin.

    • one year ago
  2. darkb0nebeauty
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    can u help me...

    • one year ago
  3. Frostbite
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    Why don't you just multiply the wavelength of an X-ray with 1000 in order to get the wavewength of a UV ray?

    • one year ago
  4. Frostbite
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    Not sure, but sounds like that it is only that.

    • one year ago
  5. Frostbite
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    beside we know that X-rays have a wavelength on about 100 nano meter.. if we take 10^-10 meter and convert to nano meters.. we get 0.1 nm. Multiply that with 1000 and you get 100 nm.

    • one year ago
  6. darkb0nebeauty
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    ok so 10^-10m * 1000

    • one year ago
  7. Frostbite
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    if I had to guess, yes. Because we know the multiplication factor and one of the wavelengths. However if I were you I would calculate in nano meters. nano = 10^-9

    • one year ago
  8. darkb0nebeauty
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    ok this wat i got = 1000000000000

    • one year ago
  9. Frostbite
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    wait.. how did you get that huge number?

    • one year ago
  10. darkb0nebeauty
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    i got t bye mulitplyn 10^-9*1000

    • one year ago
  11. Frostbite
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    I doubt that. Lets do it in the head: \[10^{-9}*1000=10^{-9}*10^{3}=10^{-9+3}=10^{-6}\]

    • one year ago
  12. darkb0nebeauty
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    oh ok so the answer is 10^-6

    • one year ago
  13. Frostbite
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    wait...

    • one year ago
  14. Frostbite
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    it was not 10^-9 but 10^-10

    • one year ago
  15. Frostbite
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    \[10^{-10} m*1000=10^{-10} m *10^{3}=10^{-10+3} m=10^{-7} m\] \[10^{-7} m * 10^{9} \frac{ nm }{ m }=100 nm\]

    • one year ago
  16. darkb0nebeauty
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    so 100nm is that right

    • one year ago
  17. Frostbite
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    Yes 100 nano meters :)

    • one year ago
  18. Frostbite
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    I think. not 100% sure if the procedure is right... seems to esay for some reason.

    • one year ago
  19. darkb0nebeauty
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    ok so 100nm, can you help me with another one

    • one year ago
  20. Frostbite
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    Just post it then I might take a look :)

    • one year ago
  21. Frostbite
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    I ment as a question :)

    • one year ago
  22. darkb0nebeauty
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    Consider the sequence 2, 6, 18, 54…. Let n= the term number in the sequence. Let A (n) = the value of the nth term of the sequence. 4. What is the common ratio of the sequence? Common ratio: 5. Complete each statement. a. A (1) =2=2*3^? b. A (2) =6=2*3=2*3^? c. A (3) =18=2*3*3=2*3^? d. A (4) =54=2*3*3*3=2*3^? 6. What is the relationship between the exponent of the base 3 and the value of n? 7. Complete the statement: A (n) = 2*3^?

    • one year ago
  23. Frostbite
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    Hmmm I think you need to post this as a seperate question, not sure I fully understand the question.

    • one year ago
  24. darkb0nebeauty
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    Activity 2 Consider the sequence 2, 6, 18, 54…. Let n= the term number in the sequence. Let A (n) = the value of the nth term of the sequence. 4. What is the common ratio of the sequence? Common ratio: 5. Complete each statement. a. A (1) =2=2*3^? b. A (2) =6=2*3=2*3^? c. A (3) =18=2*3*3=2*3^? d. A (4) =54=2*3*3*3=2*3^?

    • one year ago
  25. Frostbite
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    I just ment i don't understand the way they put it... I'm not from the US so I have to translate the words back and forth, and when I do so I get something that don't make sence. All I can say is that you can discribe your function/seq as this: A(n)=2*3^n, n belongs to all whole positive numbers.

    • one year ago
  26. darkb0nebeauty
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    ok, is that is that all you get. @Frostbite wat bout you @aspenfields

    • one year ago
  27. aspenfields
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    im just thinking and trying to figure it out atm

    • one year ago
  28. darkb0nebeauty
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    haye ca you put that work back to the first one please...@Frostbite

    • one year ago
  29. tayluvsya
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    @skullpatrol

    • one year ago
  30. darkb0nebeauty
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    ok while we are waitin for that one can u help me with this other one...please!!!

    • one year ago
  31. tayluvsya
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    which one

    • one year ago
  32. darkb0nebeauty
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    A. What is the common ratio of the sequence 80, 20, 5, 5/4…? Common ratio: B. What are the next three terms in the sequence? Next three terms:

    • one year ago
  33. darkb0nebeauty
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    haye can you please help.... @skullpatrol

    • one year ago
  34. skullpatrol
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    Any ideas?

    • one year ago
  35. darkb0nebeauty
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    ok are you going tew help me on the first one or the next three term, but with the first one o idea and the second one i do i have 1 idea

    • one year ago
  36. skullpatrol
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    What number do you need to multiply by 80 to get 20?

    • one year ago
  37. darkb0nebeauty
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    you cant muliply anything by 80 to get 20 but 20*4 is 80

    • one year ago
  38. skullpatrol
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    How about $$\frac{1}{4}$$

    • one year ago
  39. darkb0nebeauty
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    oh so 80 tmes 1/4 is 20

    • one year ago
  40. skullpatrol
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    $$80*\frac{1}{4}=20$$

    • one year ago
  41. darkb0nebeauty
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    oh ok so 20*1/4=5

    • one year ago
  42. skullpatrol
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    Yes.

    • one year ago
  43. darkb0nebeauty
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    thanks so much ok so can you help me on the other one now.... the first one or do you want me to post it up there

    • one year ago
  44. darkb0nebeauty
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    wait can you help me on the next three terms

    • one year ago
  45. skullpatrol
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    Just keep multiplying by 1/4...

    • one year ago
  46. darkb0nebeauty
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    ok is the next term 5/16, then 5/64, then 5/256

    • one year ago
  47. darkb0nebeauty
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    is that right

    • one year ago
  48. darkb0nebeauty
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    are yall still there.@skullpatrol @tayluvsya

    • one year ago
  49. darkb0nebeauty
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    @skullpatrol

    • one year ago
  50. skullpatrol
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    Correct.

    • one year ago
  51. darkb0nebeauty
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    so i did it right. ok so can you help me on the first one

    • one year ago
  52. darkb0nebeauty
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    i really dont get so can you please help me

    • one year ago
  53. skullpatrol
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    What was the question?

    • one year ago
  54. darkb0nebeauty
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    Activity 2 Consider the sequence 2, 6, 18, 54…. Let n= the term number in the sequence. Let A (n) = the value of the nth term of the sequence. 4. What is the common ratio of the sequence? Common ratio: 5. Complete each statement. a. A (1) =2=2*3^? b. A (2) =6=2*3=2*3^? c. A (3) =18=2*3*3=2*3^? d. A (4) =54=2*3*3*3=2*3^?

    • one year ago
  55. skullpatrol
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    What do you have to multiply 2 by to get 6?

    • one year ago
  56. darkb0nebeauty
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    3

    • one year ago
  57. darkb0nebeauty
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    so all of them are three is that alright

    • one year ago
  58. skullpatrol
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    Just like multiplying by 1/4 each time.

    • one year ago
  59. darkb0nebeauty
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    ok that i dont get can you please help me i have to turn this in before 12:30

    • one year ago
  60. skullpatrol
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    To get the next term multiply by 3

    • one year ago
  61. darkb0nebeauty
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    so a. 6 b.18 c.54 d. 162 is that right

    • one year ago
  62. skullpatrol
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    Yes.

    • one year ago
  63. skullpatrol
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    The whole idea behind these type of questions is to answer: "what do I need to multiply by to get the next term"? and then continue using that number.

    • one year ago
  64. darkb0nebeauty
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    so what i got up there are those the right answers....

    • one year ago
  65. skullpatrol
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    Yes.

    • one year ago
  66. darkb0nebeauty
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    ok i have 3 more

    • one year ago
  67. darkb0nebeauty
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    actually it comes along with it, look back up with the one we just worked out and it says the common ratio, is the ratio times 1/4 or what

    • one year ago
  68. darkb0nebeauty
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    haye wat happened @skullpatrol

    • one year ago
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