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brookester6

  • 3 years ago

Use any method to solve the linear system: y=1/3x+2 2x-6y=16

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  1. brookester6
    • 3 years ago
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    I'm guessing i should use substitution but I'm not sure :/

  2. SmokeysTheName
    • 3 years ago
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    in the first equation get the y to the opposite side and the 2 to the other side. so it should be -2=1/3x-y

  3. brookester6
    • 3 years ago
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    well since y is already solved shouldn't I just plug it in to the second equation???

  4. SmokeysTheName
    • 3 years ago
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    oh man, lol i was going to do elimination but yeah you're right lol plug it into the 2nd equation

  5. brookester6
    • 3 years ago
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    kk, when I did that and tried to solvee, x=10 over 3 or 10 thirds

  6. SmokeysTheName
    • 3 years ago
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    thats weird, i went through it and distributed -6 to 1/3 x and 2 and got 2x-2x-12=16

  7. SmokeysTheName
    • 3 years ago
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    so the 2x's would cancel so that wouldn't work,

  8. SmokeysTheName
    • 3 years ago
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    well lets continue doing it the way i was with elimination because that seems easier... so when we put the y to the other side we will get 1/3x-y=-2 to get the y's to cancel out we would multiply that equation by -6 to get 2x+6y=-2 combine those equations and get 2x+2x+6y-6y=14 4x=14 divide 4 from both sides and get x=3.5 understand?

  9. SmokeysTheName
    • 3 years ago
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    @brookester6 do you understand it?

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