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brookester6Best ResponseYou've already chosen the best response.0
I'm guessing i should use substitution but I'm not sure :/
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.0
in the first equation get the y to the opposite side and the 2 to the other side. so it should be 2=1/3xy
 one year ago

brookester6Best ResponseYou've already chosen the best response.0
well since y is already solved shouldn't I just plug it in to the second equation???
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.0
oh man, lol i was going to do elimination but yeah you're right lol plug it into the 2nd equation
 one year ago

brookester6Best ResponseYou've already chosen the best response.0
kk, when I did that and tried to solvee, x=10 over 3 or 10 thirds
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.0
thats weird, i went through it and distributed 6 to 1/3 x and 2 and got 2x2x12=16
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.0
so the 2x's would cancel so that wouldn't work,
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.0
well lets continue doing it the way i was with elimination because that seems easier... so when we put the y to the other side we will get 1/3xy=2 to get the y's to cancel out we would multiply that equation by 6 to get 2x+6y=2 combine those equations and get 2x+2x+6y6y=14 4x=14 divide 4 from both sides and get x=3.5 understand?
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.0
@brookester6 do you understand it?
 one year ago
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