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anonymous
 3 years ago
What makes this linear ODE linear?
anonymous
 3 years ago
What makes this linear ODE linear?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359520701118:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And is it a mistake that it says dx/dy instead of dy/dx ?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Hmm I'm pretty sure this is not linear is either x or y. Does the book say it is? :o

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's not from the book, straight from my prof. :/

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Hmm ok maybe I'm mistaken c: Gimme few minutes to think about it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the question is... explain why this ODE is linear and then solve it..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0haha, that's okay, but then again... i'm screwed if YOU can't get it!

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1OH yes maybe it is a typo! Because it appears to be linear if that derivative term is dy/dx.

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Otherwise I don't see a way to make it linear in x or y. Man I just took Diff EQ last semester, you would think I had remembered some of it :P grr

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0haha alrighty thanks. I will check with my prof.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@zepdrix, if it was dy/dx... What makes it learn? Just that it is in the right form?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Ummmm because we can get it into the form,\[\large y'+p(x)y=q(x)\] See how this form has no powers on y, and no weird functions of y,`like cos y`? If I remember correctly that's what makes it linear, if we can put it into that form.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay, cool.. Sorta what I was thinking! Thanks again
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