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baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359520701118:dw

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0And is it a mistake that it says dx/dy instead of dy/dx ?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Hmm I'm pretty sure this is not linear is either x or y. Does the book say it is? :o

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0It's not from the book, straight from my prof. :/

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Hmm ok maybe I'm mistaken c: Gimme few minutes to think about it.

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0the question is... explain why this ODE is linear and then solve it..

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0haha, that's okay, but then again... i'm screwed if YOU can't get it!

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1OH yes maybe it is a typo! Because it appears to be linear if that derivative term is dy/dx.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Otherwise I don't see a way to make it linear in x or y. Man I just took Diff EQ last semester, you would think I had remembered some of it :P grr

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0haha alrighty thanks. I will check with my prof.

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0@zepdrix, if it was dy/dx... What makes it learn? Just that it is in the right form?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Ummmm because we can get it into the form,\[\large y'+p(x)y=q(x)\] See how this form has no powers on y, and no weird functions of y,`like cos y`? If I remember correctly that's what makes it linear, if we can put it into that form.

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0okay, cool.. Sorta what I was thinking! Thanks again
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