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NotTim

  • 2 years ago

For sulfurous acid, the Ka1=?

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  1. NotTim
    • 2 years ago
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    Doing review here, and...I don't think I remember the unit

  2. NotTim
    • 2 years ago
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    \[K _{a _{1}}\]

  3. NotTim
    • 2 years ago
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    For sulfurous acid, the concrentration something is...

  4. NotTim
    • 2 years ago
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    I don't think math is involved...is it?

  5. NotTim
    • 2 years ago
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    This is a multiple choice thing...

  6. NotTim
    • 2 years ago
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    [SO32-][H1+]2 / [H2SO3] d. [HSO31-][H1+] / [H2SO3] [HSO42-][H1+] / [H2SO3] e. [H2SO3] / [SO31-][H1+]2 [SO31-][H1+]2 / [H2SO3]

  7. NotTim
    • 2 years ago
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  8. NotTim
    • 2 years ago
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    there's the question. here's the review pakage file

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  9. abb0t
    • 2 years ago
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    Well, if I remember correctly, it's a two step process for the dissociation of sulfurous acid... you can rule out option B because sulfurous acid has 3 oxygens, not 4. You can also rule out option A and C because those would be Ka2 after dissociation. And you're left with E and D. And to find K, it's products over reactants, so my guess is that it's option D.

  10. NotTim
    • 2 years ago
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    Why was SO3^2- a reactant (in the other answers)?

  11. abb0t
    • 2 years ago
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    Like I said before, it's a two step process. Seeing as how sulfurous acid is a pretty strong acid, it will completely dissociate both hydrogens. 2 moles of H+ per mole of acid.

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