NotTim
  • NotTim
For sulfurous acid, the Ka1=?
Chemistry
chestercat
  • chestercat
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NotTim
  • NotTim
Doing review here, and...I don't think I remember the unit
NotTim
  • NotTim
\[K _{a _{1}}\]
NotTim
  • NotTim
For sulfurous acid, the concrentration something is...

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NotTim
  • NotTim
I don't think math is involved...is it?
NotTim
  • NotTim
This is a multiple choice thing...
NotTim
  • NotTim
[SO32-][H1+]2 / [H2SO3] d. [HSO31-][H1+] / [H2SO3] [HSO42-][H1+] / [H2SO3] e. [H2SO3] / [SO31-][H1+]2 [SO31-][H1+]2 / [H2SO3]
NotTim
  • NotTim
1 Attachment
NotTim
  • NotTim
there's the question. here's the review pakage file
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abb0t
  • abb0t
Well, if I remember correctly, it's a two step process for the dissociation of sulfurous acid... you can rule out option B because sulfurous acid has 3 oxygens, not 4. You can also rule out option A and C because those would be Ka2 after dissociation. And you're left with E and D. And to find K, it's products over reactants, so my guess is that it's option D.
NotTim
  • NotTim
Why was SO3^2- a reactant (in the other answers)?
abb0t
  • abb0t
Like I said before, it's a two step process. Seeing as how sulfurous acid is a pretty strong acid, it will completely dissociate both hydrogens. 2 moles of H+ per mole of acid.

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