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 one year ago
Let A be a 3 × 3 matrix whose entries are 17 or 0. What is the largest possible value for det(A) ?
 one year ago
Let A be a 3 × 3 matrix whose entries are 17 or 0. What is the largest possible value for det(A) ?

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Dido525
 one year ago
Best ResponseYou've already chosen the best response.0Since it say's OR I am actually not sure how I would do this. Setting all the entries to 17 simply makes the determinant 0.

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0true because all would be 0

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359528317295:dw

Dido525
 one year ago
Best ResponseYou've already chosen the best response.0That's such a stupid question then...

Dido525
 one year ago
Best ResponseYou've already chosen the best response.0Are you sure though? What if some of them are 17 and some of them are 1?

Dido525
 one year ago
Best ResponseYou've already chosen the best response.0Like if I change 2 of those to 0 the determininant become 4913 all of a sudden.

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0maybe thinking off this as M or C matrices i forgot what they're called

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359528522846:dw

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0now each one of those cofactors i think they're called =dw:1359528606154:dw

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0that's why you'll get zero if you put 17's all in it

Dido525
 one year ago
Best ResponseYou've already chosen the best response.0Okay but what if I put SOME of them as 17 and SOME of them as 0. Then it a lot bigger.

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0there was also a theory i think if i remember that if you somehow prove that two vectors are just combinations of the other... then you can prove it's zero also

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0because if two are the combinations of each other than you can reduce them down to [17 17 17] and then if you can easily get a row of zeroes

Dido525
 one year ago
Best ResponseYou've already chosen the best response.0SO clearly, there is a maximum.

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359528911003:dw

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359528962928:dw

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0is this what you got?

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0so i'm thinking the rule is the largest determinant comes from having vectors that are dependent of one anothre

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0i mean independent

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0so the largest happens when all are independent of one another
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