Let A be a 3 × 3 matrix whose entries are 17 or 0. What is the largest possible value for det(A) ?

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Let A be a 3 × 3 matrix whose entries are 17 or 0. What is the largest possible value for det(A) ?

Mathematics
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Since it say's OR I am actually not sure how I would do this. Setting all the entries to 17 simply makes the determinant 0.
true because all would be 0
|dw:1359528317295:dw|

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That's such a stupid question then...
Are you sure though? What if some of them are 17 and some of them are 1?
0* now 1 sorry.
not*
Like if I change 2 of those to 0 the determininant become 4913 all of a sudden.
maybe thinking off this as M or C matrices i forgot what they're called
Cofactor?
|dw:1359528522846:dw|
now each one of those cofactors i think they're called =|dw:1359528606154:dw|
that's why you'll get zero if you put 17's all in it
Okay but what if I put SOME of them as 17 and SOME of them as 0. Then it a lot bigger.
there was also a theory i think if i remember that if you somehow prove that two vectors are just combinations of the other... then you can prove it's zero also
because if two are the combinations of each other than you can reduce them down to [17 17 17] and then if you can easily get a row of zeroes
|dw:1359528822331:dw|
THat's 4913.
SO clearly, there is a maximum.
|dw:1359528911003:dw|
Nvm, I got it.
|dw:1359528962928:dw|
is this what you got?
so i'm thinking the rule is the largest determinant comes from having vectors that are dependent of one anothre
i mean independent
so the largest happens when all are independent of one another

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