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cos(4x)=cos(2x+2x)
expand that^

\(\cos4x=1-2\sin^2 2x\)
\(\cos2x=1-2\sin^2x\)
does that help?

It did, but could you please show me how cos 4x = 1 - 2 sin^2 2x?

\(\cos^2x+\sin^2x=1\)
Similarly
\(\cos^2 2x+\sin^2 2x=1\)
\(\cos^2 2x=1-\sin^2 2x\)

Thank you for your time and assistance. :)

Welcome:)