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sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0what the heck do you do after this

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.0are those 9's inside radical ?

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0you dont have to write the whole steps like last time can you just give me advice and yes they are

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0and you can just make them easy by making them into (3/7x)^2

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1359530730683:dw (3/7x)^2 something like that for the bottom part

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0when you do it can you confirm that you get the same solution as in my solving part and help me from there on. thanks

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.0ok i get same solution (i simplified the constants) \[\frac{343}{81}(\frac{\sec^{3} \theta}{3}  \sec \theta) +C\] now you have to substitute back in "x" \[\tan \theta = \frac{3x}{7}\] and \[\sec^{2} \theta = \tan^{2} +1 = \frac{9x^{2}}{49} +1 = \frac{9x^{2} +49}{49}\] take sqrt to get "sec" , then cube that to get sec^3

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0so you wouldd ger 3x +7 /7 ?

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.0no it would be ... sqrt(9x^2 +49) /7 because of addition inside you can't just take sqrt of each term

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0oh right right silly me

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.0yep ... oh dont forget the 3 in denominator probably need to s.continue to simplify

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0but hold on my angles look like this dw:1359532285169:dw

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.0hmm hypotenuse should be .... sqrt(9x^2 +49)

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0oh f i see why i forgot to square. its 2am and i had a long day .

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.0haha time to get some sleep ....have wolfram do work for you

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0yep just finished it got the right answer thanks a lot time for bed i cant even think straight right now

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.0yeah about 1 am here in AZ (best state)

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0and dont use wolfram like to get these things down myself

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0taking engineering math not my strongest subject but where the jobs go i go XD

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.0nope... finished with college , i work as a math tutor so i come on here to practice and help people

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0hmm so you planning to be a teacher you would be a good one

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.0engineering is great field but tough classes have to take quite a bit of math

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0yep still got to diff linear algebra etc good night bed is calling for me :P

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.0i qualified to be a teacher but am undecided .... i prefer tutoring 1 on 1 ..... classroom teaching isn't my style

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0you would be a great 1 v1 tutor too yea good night
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