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well did you try variable separation method?

hint :\[\large e^{x-y}=\dfrac{e^x}{e^y}\]

you are right !! :)

now use y(1) to get c

what I got was right... okay, so then I would just plug in the 0 and 1 and find c

0 = ln | ln | 2 + e^1 | + C |

umm 0 = ln |2 + e^1| + C
how do I find C, or do I just make it a decimal

C=-ln|2+e|