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zonazoo

  • one year ago

Find a solution of the intial value problem. dy/dx = (e^(x-y))/(1+e^x), y(1)=0

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  1. AravindG
    • one year ago
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    well did you try variable separation method?

  2. zonazoo
    • one year ago
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    I did, and not sure if I am right. But i am at. y = ln | ln | 1 + e^x | + c | but it looks wrong to me

  3. AravindG
    • one year ago
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    hint :\[\large e^{x-y}=\dfrac{e^x}{e^y}\]

  4. AravindG
    • one year ago
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    you are right !! :)

  5. AravindG
    • one year ago
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    now use y(1) to get c

  6. zonazoo
    • one year ago
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    what I got was right... okay, so then I would just plug in the 0 and 1 and find c

  7. zonazoo
    • one year ago
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    0 = ln | ln | 2 + e^1 | + C |

  8. zonazoo
    • one year ago
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    umm 0 = ln |2 + e^1| + C how do I find C, or do I just make it a decimal

  9. AravindG
    • one year ago
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    C=-ln|2+e|

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