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zonazoo

Find a solution of the intial value problem. dy/dx = (e^(x-y))/(1+e^x), y(1)=0

  • one year ago
  • one year ago

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  1. AravindG
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    well did you try variable separation method?

    • one year ago
  2. zonazoo
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    I did, and not sure if I am right. But i am at. y = ln | ln | 1 + e^x | + c | but it looks wrong to me

    • one year ago
  3. AravindG
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    hint :\[\large e^{x-y}=\dfrac{e^x}{e^y}\]

    • one year ago
  4. AravindG
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    you are right !! :)

    • one year ago
  5. AravindG
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    now use y(1) to get c

    • one year ago
  6. zonazoo
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    what I got was right... okay, so then I would just plug in the 0 and 1 and find c

    • one year ago
  7. zonazoo
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    0 = ln | ln | 2 + e^1 | + C |

    • one year ago
  8. zonazoo
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    umm 0 = ln |2 + e^1| + C how do I find C, or do I just make it a decimal

    • one year ago
  9. AravindG
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    C=-ln|2+e|

    • one year ago
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