Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Yahoo! Group Title

A vessel in the form of an inverted cone of height 10 feet and semi vertical angle 30 is filled with a solution. this solution is drained through an orifice at its bottom into a cylindrical beaker of radius sqrt6 feet in such a way that the height of the solution in the conical vessel decreases at a uniform rate of 2 inch/min. Find the rate at which the height of the solution increases in the beaker when the height of the solution column in the conical vessel is 6 ft?

  • one year ago
  • one year ago

  • This Question is Closed
  1. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1359555212522:dw| is this the figure?

    • one year ago
  2. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[ V = \frac 1 3 \pi R^2 h, \;\;R = h \tan 30 \\ \frac{dV}{dt} = \frac 1 3 \pi R^2 \frac {dh}{dt}\] Put h = 6, this will give you rate of increase of volume. do same for cylinder.

    • one year ago
  3. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    and put dh/dt = 2

    • one year ago
  4. shubhamsrg Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    The semi vertical angle is 30 @experimentX

    • one year ago
  5. shubhamsrg Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1359560975070:dw|

    • one year ago
  6. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    oh .. my bad!!

    • one year ago
  7. shubhamsrg Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    So the working eqns will be : V = pi/3 R^2 h => dV/dt = pi/3 (2R) (dR/dt) (dh/dt) We know cot30 = h/R => dR/dt cot30 = dh/dt Make that substitution. For cylinder, V = pi r^2 h dV/dt = pi r^2 dh/dt equate both dV/dt 's so find dh/dt for cylinder.

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.