## Yahoo! Group Title A vessel in the form of an inverted cone of height 10 feet and semi vertical angle 30 is filled with a solution. this solution is drained through an orifice at its bottom into a cylindrical beaker of radius sqrt6 feet in such a way that the height of the solution in the conical vessel decreases at a uniform rate of 2 inch/min. Find the rate at which the height of the solution increases in the beaker when the height of the solution column in the conical vessel is 6 ft? one year ago one year ago

1. experimentX

|dw:1359555212522:dw| is this the figure?

2. experimentX

$V = \frac 1 3 \pi R^2 h, \;\;R = h \tan 30 \\ \frac{dV}{dt} = \frac 1 3 \pi R^2 \frac {dh}{dt}$ Put h = 6, this will give you rate of increase of volume. do same for cylinder.

3. experimentX

and put dh/dt = 2

4. shubhamsrg

The semi vertical angle is 30 @experimentX

5. shubhamsrg

|dw:1359560975070:dw|

6. experimentX