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dedderick

  • 2 years ago

In the diagram, if EC = 8, ED = 6 and AE = 12 solve for EB.

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  1. dedderick
    • 2 years ago
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  2. dedderick
    • 2 years ago
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    i really need help

  3. shreya.
    • 2 years ago
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    the rectangle formed by these chords is equal in area.

  4. dedderick
    • 2 years ago
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    do u know the answer and the reason

  5. shreya.
    • 2 years ago
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    EB*AE= CE*DE

  6. shreya.
    • 2 years ago
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    its a theorem , that if two chords of a circle intersect each other inside or outside a circle when produced , the rect formed by the 2 segments of the chord is qual to that of the other two segments

  7. dedderick
    • 2 years ago
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    these are the answers: 2,4,6,8,

  8. salma1996
    • 2 years ago
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    Which rectangles do you mean?

  9. dedderick
    • 2 years ago
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    there's no rectangle

  10. shreya.
    • 2 years ago
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    4 is the ans. and if you take the sides EB and AE as the sides of a rectangle and CE and DE as the sides of some other rectangle.., then their areas will be same

  11. shreya.
    • 2 years ago
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    did u get it ??

  12. dedderick
    • 2 years ago
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    yes thank u

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