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dedderick Group Title

In the diagram, if EC = 8, ED = 6 and AE = 12 solve for EB.

  • one year ago
  • one year ago

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  1. dedderick Group Title
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    • one year ago
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  2. dedderick Group Title
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    i really need help

    • one year ago
  3. shreya. Group Title
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    the rectangle formed by these chords is equal in area.

    • one year ago
  4. dedderick Group Title
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    do u know the answer and the reason

    • one year ago
  5. shreya. Group Title
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    EB*AE= CE*DE

    • one year ago
  6. shreya. Group Title
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    its a theorem , that if two chords of a circle intersect each other inside or outside a circle when produced , the rect formed by the 2 segments of the chord is qual to that of the other two segments

    • one year ago
  7. dedderick Group Title
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    these are the answers: 2,4,6,8,

    • one year ago
  8. salma1996 Group Title
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    Which rectangles do you mean?

    • one year ago
  9. dedderick Group Title
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    there's no rectangle

    • one year ago
  10. shreya. Group Title
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    4 is the ans. and if you take the sides EB and AE as the sides of a rectangle and CE and DE as the sides of some other rectangle.., then their areas will be same

    • one year ago
  11. shreya. Group Title
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    did u get it ??

    • one year ago
  12. dedderick Group Title
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    yes thank u

    • one year ago
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