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dedderick
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In the diagram, if EC = 8, ED = 6 and AE = 12 solve for EB.
 one year ago
 one year ago
dedderick Group Title
In the diagram, if EC = 8, ED = 6 and AE = 12 solve for EB.
 one year ago
 one year ago

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dedderick Group TitleBest ResponseYou've already chosen the best response.0
i really need help
 one year ago

shreya. Group TitleBest ResponseYou've already chosen the best response.0
the rectangle formed by these chords is equal in area.
 one year ago

dedderick Group TitleBest ResponseYou've already chosen the best response.0
do u know the answer and the reason
 one year ago

shreya. Group TitleBest ResponseYou've already chosen the best response.0
EB*AE= CE*DE
 one year ago

shreya. Group TitleBest ResponseYou've already chosen the best response.0
its a theorem , that if two chords of a circle intersect each other inside or outside a circle when produced , the rect formed by the 2 segments of the chord is qual to that of the other two segments
 one year ago

dedderick Group TitleBest ResponseYou've already chosen the best response.0
these are the answers: 2,4,6,8,
 one year ago

salma1996 Group TitleBest ResponseYou've already chosen the best response.0
Which rectangles do you mean?
 one year ago

dedderick Group TitleBest ResponseYou've already chosen the best response.0
there's no rectangle
 one year ago

shreya. Group TitleBest ResponseYou've already chosen the best response.0
4 is the ans. and if you take the sides EB and AE as the sides of a rectangle and CE and DE as the sides of some other rectangle.., then their areas will be same
 one year ago

shreya. Group TitleBest ResponseYou've already chosen the best response.0
did u get it ??
 one year ago

dedderick Group TitleBest ResponseYou've already chosen the best response.0
yes thank u
 one year ago
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