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anonymous
 3 years ago
In the diagram, if EC = 8, ED = 6 and AE = 12 solve for EB.
anonymous
 3 years ago
In the diagram, if EC = 8, ED = 6 and AE = 12 solve for EB.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the rectangle formed by these chords is equal in area.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do u know the answer and the reason

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its a theorem , that if two chords of a circle intersect each other inside or outside a circle when produced , the rect formed by the 2 segments of the chord is qual to that of the other two segments

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0these are the answers: 2,4,6,8,

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Which rectangles do you mean?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.04 is the ans. and if you take the sides EB and AE as the sides of a rectangle and CE and DE as the sides of some other rectangle.., then their areas will be same
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