Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Yahoo!
Group Title
\[\lim_{n \rightarrow \infty} \frac{ [\sum_{r=1}^{2n1 }(sr1 ]^3 }{[ \sum_{r=1}^{2n1}(sr1)^2]^2 }\]
 one year ago
 one year ago
Yahoo! Group Title
\[\lim_{n \rightarrow \infty} \frac{ [\sum_{r=1}^{2n1 }(sr1 ]^3 }{[ \sum_{r=1}^{2n1}(sr1)^2]^2 }\]
 one year ago
 one year ago

This Question is Closed

experimentX Group TitleBest ResponseYou've already chosen the best response.0
what the hell is that??
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
exand the summation inside ,, its arithmetic series, and constant. express it in compact form and do business with cube and square outside.
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
What is the difference between numerator and denom ? except for sq. and cube.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{n \rightarrow \infty} \frac{ [\sum_{r=1}^{2n1 }(sr1 ]^3 }{[ \sum_{r=1}^{2n1}(sr1)^2]^2 }\]
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
[ (s1) + (2s1) +(3s1) ...((2n1)s 1) ]^3  [ (s1)^2 + (2s1)^2 ...... ((2n1)s 1)^2 ]^2
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Sr  = s1 , s2 , s3 , s4 ...................
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
numerator = [ s + 2s +3s .. (2n1)s  (2n1) ]^3 denominator = [ s^2 + (2s^2) ..((2n1)s)^2  2s(1+2+3..(2n1)) +(2n1) ]^2 This should help ?
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.