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 one year ago
\[\lim_{n \rightarrow \infty} \frac{ [\sum_{r=1}^{2n1 }(sr1 ]^3 }{[ \sum_{r=1}^{2n1}(sr1)^2]^2 }\]
 one year ago
\[\lim_{n \rightarrow \infty} \frac{ [\sum_{r=1}^{2n1 }(sr1 ]^3 }{[ \sum_{r=1}^{2n1}(sr1)^2]^2 }\]

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experimentX
 one year ago
Best ResponseYou've already chosen the best response.0what the hell is that??

experimentX
 one year ago
Best ResponseYou've already chosen the best response.0exand the summation inside ,, its arithmetic series, and constant. express it in compact form and do business with cube and square outside.

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.0What is the difference between numerator and denom ? except for sq. and cube.

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0\[\lim_{n \rightarrow \infty} \frac{ [\sum_{r=1}^{2n1 }(sr1 ]^3 }{[ \sum_{r=1}^{2n1}(sr1)^2]^2 }\]

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.0[ (s1) + (2s1) +(3s1) ...((2n1)s 1) ]^3  [ (s1)^2 + (2s1)^2 ...... ((2n1)s 1)^2 ]^2

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0Sr  = s1 , s2 , s3 , s4 ...................

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.0numerator = [ s + 2s +3s .. (2n1)s  (2n1) ]^3 denominator = [ s^2 + (2s^2) ..((2n1)s)^2  2s(1+2+3..(2n1)) +(2n1) ]^2 This should help ?
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