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Diwakar
Group Title
In the expression for entropy
we write : delta S = q/T. But it is also mentioned that the process in which heat is added is reversible.
Why should the process be reversible?
 one year ago
 one year ago
Diwakar Group Title
In the expression for entropy we write : delta S = q/T. But it is also mentioned that the process in which heat is added is reversible. Why should the process be reversible?
 one year ago
 one year ago

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Diwakar Group TitleBest ResponseYou've already chosen the best response.0
@shubhamsrg
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
I don;t know/remember the exact and proper reasoning for this. But I'll find out soon and tell you . :)
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
@VincentLyon.Fr
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Actually, it is dS = dq/T (dS and dq are infinitesimal) If the process is not reversible, unfortunately, dS > dq/T, but we do not know by how much.
 one year ago
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