Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Diwakar

  • one year ago

In the expression for entropy we write : delta S = q/T. But it is also mentioned that the process in which heat is added is reversible. Why should the process be reversible?

  • This Question is Closed
  1. Diwakar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @shubhamsrg

  2. shubhamsrg
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don;t know/remember the exact and proper reasoning for this. But I'll find out soon and tell you . :)

  3. shubhamsrg
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Vincent-Lyon.Fr

  4. Vincent-Lyon.Fr
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Actually, it is dS = dq/T (dS and dq are infinitesimal) If the process is not reversible, unfortunately, dS > dq/T, but we do not know by how much.

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.