math0101
If x = 4t and y = 205t^2, what is the equation of the straight line?



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precal
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x=4t solve for t and then sub into the second equation

math0101
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ah....
so t = x/4
y = 20  5t^2
y = 20  (5x^2)/4

math0101
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y = 20  5x/16

precal
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dw:1359564389686:dw

precal
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dw:1359564417898:dw

precal
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you dropped your second power

math0101
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hmm...

precal
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dw:1359564546497:dw

precal
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dw:1359564574634:dw

math0101
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ah! ok, now I see :)

math0101
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thanks!

precal
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yw