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math0101

  • 3 years ago

If x = 4t and y = 20-5t^2, what is the equation of the straight line?

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  1. precal
    • 3 years ago
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    x=4t solve for t and then sub into the second equation

  2. math0101
    • 3 years ago
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    ah.... so t = x/4 y = 20 - 5t^2 y = 20 - (5x^2)/4

  3. math0101
    • 3 years ago
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    y = 20 - 5x/16

  4. precal
    • 3 years ago
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    |dw:1359564389686:dw|

  5. precal
    • 3 years ago
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    |dw:1359564417898:dw|

  6. precal
    • 3 years ago
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    you dropped your second power

  7. math0101
    • 3 years ago
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    hmm...

  8. precal
    • 3 years ago
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    |dw:1359564546497:dw|

  9. precal
    • 3 years ago
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    |dw:1359564574634:dw|

  10. math0101
    • 3 years ago
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    ah! ok, now I see :)

  11. math0101
    • 3 years ago
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    thanks!

  12. precal
    • 3 years ago
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    yw

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