Please help me! Thank you! (◕‿◕✿)
Part 1: Solve the inequality 12 + 4x ≤ 5x - 2 and show all of your work. You can use <= to represent the less than or equal to symbol.
Part 2: Use complete sentences to describe the graph of the solution from Part 1. Be sure to include the type of circle and which direction the shading will be.
Note: I'm only having trouble with Part 2!

- RealityWillSlapYou

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- precal

|dw:1359578294688:dw|

- RealityWillSlapYou

@precal, thank you for that wonderful graph you made for me, however I need it to be described.... meaning that I need it in words. I thank you again it is a help just not the help I need right now. :D

- precal

well you can use your own words to describe the solutions

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## More answers

- precal

did they want the negative numbers? zero? positive numbers? Is 14 part of the solution?

- RealityWillSlapYou

I'm not really sure they weren't very detailed.

- RealityWillSlapYou

I am really bad at math, so it's extremely hard for me to describe it and put it into words

- precal

type of circle means do you use an open circle or a closed circle. I know exactly what they want but at this point it is merely a question of the usage of your english language skills

- RealityWillSlapYou

Okay...... well I tried to and I failed at it and so that's why I'm on here looking for help with this :(

- precal

well write it out and I will correct you (if needed)

- RealityWillSlapYou

You put a closed circle on 7, and shaded it to the right.

- RealityWillSlapYou

?

- precal

7 is not even the number you should be using|dw:1359578942429:dw|

- RealityWillSlapYou

But part 1 is
12 + 4x ≤ 5x -2
12 -x ≤ -2
-x ≤ -14
x ≥ 7

- RealityWillSlapYou

Right?

- precal

last step is incorrect, 14 does not turn into 7

- precal

|dw:1359579117248:dw|

- RealityWillSlapYou

Oh, I don't know how I got the 7 but some how I did! Oops!

- RealityWillSlapYou

Then it's:
You put a closed circle on 14, and shaded it to the right.

- RealityWillSlapYou

I'm I right this time?

- precal

yes but what does that all mean
closed circle, does that mean 14 is part of the solution?

- RealityWillSlapYou

I think so...

- precal

yes and if the circle is open then that would mean that 14 is not part of the solution

- precal

now what numbers do we want from the number line: negative? zero? positive?

- RealityWillSlapYou

Because of the "less then or equal to" sign I could be equal to x or it could be less then... correct?

- RealityWillSlapYou

Positive?

- RealityWillSlapYou

Because it's going to the right?

- precal

so 1,2,3,4,5, etc are all solutions?

- RealityWillSlapYou

Yes....?

- precal

|dw:1359580332816:dw|really?

- precal

gotta go in about 5 minutes you are my last question of the day

- RealityWillSlapYou

So, am I right?

- precal

14 is not less than 1,2,3,4,5,6,7,8,9,10,11,12,13

- precal

no you are not right

- precal

you want 14,15,16,17, etc
so you want 14 and all of the numbers bigger than 14

- RealityWillSlapYou

Oh, yeah that's right..... I feel dumb

- precal

np

- RealityWillSlapYou

So, I shad it to the left?

- RealityWillSlapYou

*shade

- precal

|dw:1359601055140:dw|shade to the right

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