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cherio12Best ResponseYou've already chosen the best response.1
okay well the theorem is \[z^2=x^2+y^2\] and you know everything has to be an integer (whole number)
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
you can just try different values. For instance for the first one i might try z=51 and x=24. so 51^2=24^2+y^2. Solving i get y=45. So this works
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
@cherio12 can you try #19 plz
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
you just have to play with the numbers. I first tried \[z^2=25^2+20^\] but i got z= 32.0156..so this didn't work next i tried \[25^2=20^2+y^2\] y=15 (this is an integer) so it checks out
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
does this make sense?
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
thats the answer in the book so i should be able to learn off your 2 answers
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
wait so on 18# i got 2601=576+y2 then do i get y by itself? @cherio12
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
yes. you should go 2601576=y^2. then take the squareroot of both sides to just get y
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
ok how do you know were to put the numbers on the equation?
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
wait oh i see you said move them around and it has to be a whole number
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
yup, its always (leg)^2+(leg)^2=(hypotenuse)^2
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
thanks man! helped alot
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
its commonly written as x^2+y^2=z^2
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
wait so on # 20 i got 91.82592222ect
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
okay so that means you picked the wrong combo of hypotenuse and legs. try another combo (by the way the hypotenuse will always be the largest of the 3 numbers)
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
so set it up as x2= 96 + 28?
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
i would try \[96^2=x^2+28^2\]
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
do get x by its self?
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
dw:1359577137858:dw
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
but i still will get that 91.etc right?
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
i was just showing you the triangle to help show what i meant by x, y and z
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
i know im saying when i get x by its self and take 9216 and square it i get that 91.00202 number
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
o you mean for the 96, 28 problem?
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
\[96^2=x^2+28^2\] \[9216=x^2+784\] \[9216784=x^2\] \[x=\sqrt{8432}\] x=91.8259 so this way didn't work.
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
i would then try \[z^2=96^2+28^2\]
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
but you would still get 91.8259 right?
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
you add 96^2 and 28^2 in this example instead of subtracting them (like we tried before)
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
now i see thakns agian lol
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
hey can you help @cherio12 with # 23
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
okay so i first tried z^2=72^2+75^2 But i got z=103.966 so that's not right then i tried 75^2=x^2+72^2
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
ok i did the first but didnt try that one what did you get?
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
can you show how you did that?
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
75^2=x^2+72^2 solve for x
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
hey @cherio12 for #24 you you do the same?
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
yes, your two legs are 6 and 3
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
so would it be 6(2)=3(2)+x2
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
by(2) do you mean you are squaring it?
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
no 6 to the power 2 like 6*6
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
that means squaring, but yes that is correct
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
wait that doesnt work
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
i tried both ways and got not a whole number
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
I don't believe you are supossed to get an integer for this problem
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
ya that was my second way
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
so would you set up # 25 and # 26 the same way?
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
yes for 25, but for 26 you will use a ratio
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
i gotta go eat..be back later
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
ok when you get back can you explain ratio?
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
okay well for starters find the other leg on the 5,3 triangle
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
wait on the # 25 its just 11 and x so is it 121 then sqare root answer is 11?
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
no, there are two 11 sides
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
oh i see cuase of that line thingy
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
no for 25, it is 11^1+11^2=x^2
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
does that make sense why?
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
yes i just didnt try that way and remember there not whole numbers
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
so how do you do #26 is it 2 problems in 1
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
find the other leg in the 5,3 triangle first
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
now do the other triangel?
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
now we can use like triangle ratios 4/5=7/x
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
so 4 sqare + 5 square = 7sqare?
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
just ratio, just division
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
oh ok wow being sick for one day of notes can rweally heart you
 one year ago

Nick2019Best ResponseYou've already chosen the best response.0
wait # 28 its 2x and 2x+4 and the length of the hypot is 4x4
 one year ago

cherio12Best ResponseYou've already chosen the best response.1
yes, just apply the Pythagorean theorem
 one year ago
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