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anonymous
 3 years ago
I need help!!!
anonymous
 3 years ago
I need help!!!

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay well the theorem is \[z^2=x^2+y^2\] and you know everything has to be an integer (whole number)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you can just try different values. For instance for the first one i might try z=51 and x=24. so 51^2=24^2+y^2. Solving i get y=45. So this works

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@cherio12 can you try #19 plz

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you just have to play with the numbers. I first tried \[z^2=25^2+20^\] but i got z= 32.0156..so this didn't work next i tried \[25^2=20^2+y^2\] y=15 (this is an integer) so it checks out

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0does this make sense?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thats the answer in the book so i should be able to learn off your 2 answers

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait so on 18# i got 2601=576+y2 then do i get y by itself? @cherio12

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes. you should go 2601576=y^2. then take the squareroot of both sides to just get y

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok how do you know were to put the numbers on the equation?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait oh i see you said move them around and it has to be a whole number

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yup, its always (leg)^2+(leg)^2=(hypotenuse)^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks man! helped alot

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its commonly written as x^2+y^2=z^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait so on # 20 i got 91.82592222ect

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay so that means you picked the wrong combo of hypotenuse and legs. try another combo (by the way the hypotenuse will always be the largest of the 3 numbers)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so set it up as x2= 96 + 28?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i would try \[96^2=x^2+28^2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do get x by its self?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359577137858:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but i still will get that 91.etc right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i was just showing you the triangle to help show what i meant by x, y and z

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know im saying when i get x by its self and take 9216 and square it i get that 91.00202 number

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0o you mean for the 96, 28 problem?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[96^2=x^2+28^2\] \[9216=x^2+784\] \[9216784=x^2\] \[x=\sqrt{8432}\] x=91.8259 so this way didn't work.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i would then try \[z^2=96^2+28^2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but you would still get 91.8259 right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you add 96^2 and 28^2 in this example instead of subtracting them (like we tried before)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now i see thakns agian lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hey can you help @cherio12 with # 23

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay so i first tried z^2=72^2+75^2 But i got z=103.966 so that's not right then i tried 75^2=x^2+72^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok i did the first but didnt try that one what did you get?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you show how you did that?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.075^2=x^2+72^2 solve for x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hey @cherio12 for #24 you you do the same?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, your two legs are 6 and 3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so would it be 6(2)=3(2)+x2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0by(2) do you mean you are squaring it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no 6 to the power 2 like 6*6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that means squaring, but yes that is correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait that doesnt work

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i tried both ways and got not a whole number

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't believe you are supossed to get an integer for this problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ya that was my second way

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so would you set up # 25 and # 26 the same way?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes for 25, but for 26 you will use a ratio

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i gotta go eat..be back later

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok when you get back can you explain ratio?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay well for starters find the other leg on the 5,3 triangle

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait on the # 25 its just 11 and x so is it 121 then sqare root answer is 11?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no, there are two 11 sides

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh i see cuase of that line thingy

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no for 25, it is 11^1+11^2=x^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0does that make sense why?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes i just didnt try that way and remember there not whole numbers

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so how do you do #26 is it 2 problems in 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0find the other leg in the 5,3 triangle first

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now do the other triangel?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now we can use like triangle ratios 4/5=7/x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so 4 sqare + 5 square = 7sqare?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just ratio, just division

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh ok wow being sick for one day of notes can rweally heart you

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait # 28 its 2x and 2x+4 and the length of the hypot is 4x4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, just apply the Pythagorean theorem
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