## keelyjm Group Title Help with a horizontal asymptote?? one year ago one year ago

1. amistre64 Group Title

whatcha got?

2. keelyjm Group Title

well I am trying to figure out what to put in the equation $y= \frac{ a^n }{ b^m }$

3. keelyjm Group Title

The equation is 7x^2-3x-9/2x^2-4x+5

4. amistre64 Group Title

hopefully theres more instructions than that ;)

5. amistre64 Group Title

there it is

6. amistre64 Group Title

and I take it you need to determine the HA?

7. keelyjm Group Title

yes since n=m

8. amistre64 Group Title

HAs tells us what happens for very large values of x; and as such the addons after the first terms are usless since they contribute nothing to the equation so reduce this set up to: 7x^2 ----- 2x^2 now, as x gets larger and larger you can see that x^2/x^2 really cancels out and we are left with?

9. keelyjm Group Title

7 - 2

10. amistre64 Group Title

7/2 yes. so that has to be the HA

11. keelyjm Group Title

alright and I have another one, but I think I know it now. 3x^2-4x-3/2x^2-3x+2

12. keelyjm Group Title

so it would be 3 - 2

13. amistre64 Group Title

very good :)

14. keelyjm Group Title

thank you! :)