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keelyjm

  • 2 years ago

Help with a horizontal asymptote??

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  1. amistre64
    • 2 years ago
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    whatcha got?

  2. keelyjm
    • 2 years ago
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    well I am trying to figure out what to put in the equation \[y= \frac{ a^n }{ b^m }\]

  3. keelyjm
    • 2 years ago
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    The equation is 7x^2-3x-9/2x^2-4x+5

  4. amistre64
    • 2 years ago
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    hopefully theres more instructions than that ;)

  5. amistre64
    • 2 years ago
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    there it is

  6. amistre64
    • 2 years ago
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    and I take it you need to determine the HA?

  7. keelyjm
    • 2 years ago
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    yes since n=m

  8. amistre64
    • 2 years ago
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    HAs tells us what happens for very large values of x; and as such the addons after the first terms are usless since they contribute nothing to the equation so reduce this set up to: 7x^2 ----- 2x^2 now, as x gets larger and larger you can see that x^2/x^2 really cancels out and we are left with?

  9. keelyjm
    • 2 years ago
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    7 - 2

  10. amistre64
    • 2 years ago
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    7/2 yes. so that has to be the HA

  11. keelyjm
    • 2 years ago
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    alright and I have another one, but I think I know it now. 3x^2-4x-3/2x^2-3x+2

  12. keelyjm
    • 2 years ago
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    so it would be 3 - 2

  13. amistre64
    • 2 years ago
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    very good :)

  14. keelyjm
    • 2 years ago
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    thank you! :)

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