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## keelyjm Group Title Help with a horizontal asymptote?? one year ago one year ago

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1. amistre64

whatcha got?

2. keelyjm

well I am trying to figure out what to put in the equation $y= \frac{ a^n }{ b^m }$

3. keelyjm

The equation is 7x^2-3x-9/2x^2-4x+5

4. amistre64

hopefully theres more instructions than that ;)

5. amistre64

there it is

6. amistre64

and I take it you need to determine the HA?

7. keelyjm

yes since n=m

8. amistre64

HAs tells us what happens for very large values of x; and as such the addons after the first terms are usless since they contribute nothing to the equation so reduce this set up to: 7x^2 ----- 2x^2 now, as x gets larger and larger you can see that x^2/x^2 really cancels out and we are left with?

9. keelyjm

7 - 2

10. amistre64

7/2 yes. so that has to be the HA

11. keelyjm

alright and I have another one, but I think I know it now. 3x^2-4x-3/2x^2-3x+2

12. keelyjm

so it would be 3 - 2

13. amistre64

very good :)

14. keelyjm

thank you! :)