Help with a horizontal asymptote??

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Help with a horizontal asymptote??

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

whatcha got?
well I am trying to figure out what to put in the equation \[y= \frac{ a^n }{ b^m }\]
The equation is 7x^2-3x-9/2x^2-4x+5

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

hopefully theres more instructions than that ;)
there it is
and I take it you need to determine the HA?
yes since n=m
HAs tells us what happens for very large values of x; and as such the addons after the first terms are usless since they contribute nothing to the equation so reduce this set up to: 7x^2 ----- 2x^2 now, as x gets larger and larger you can see that x^2/x^2 really cancels out and we are left with?
7 - 2
7/2 yes. so that has to be the HA
alright and I have another one, but I think I know it now. 3x^2-4x-3/2x^2-3x+2
so it would be 3 - 2
very good :)
thank you! :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question