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f(-6)=???? f(x)=square root of 5-x

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\( f(x) = \sqrt{5 - x} \) This is it, correct? So, f(-6) means x = -6 in our function. Have you tried replacing x for -6 in the function?
yes and it comes as a decimal .. 3.316
Hmm, that seems about right. I might leave it with the radical, myself, depending on if the question asks us to round or not. :)

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it wants a radical
? i dont know how to do it
\( f(-6) = \sqrt{5 - (-6)} \) \( = \sqrt{5 + 6} \) \(= \sqrt{11} \) <--- this is the radical, I think I'd leave it there if you're not asked to round \( \approx 3.316\) <--- this is your answer, which is the same.
\(\sqrt{11}\) is just a little more "accurate". :)

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