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 one year ago
Nick plotted A(2, 2), B(3, 4), and C(4, 2) and joined the points to form triangle ABC. He plotted two other points at P(3, 4) and Q(2, 2).
What should be the coordinates of the third point R to form triangle PQR that is congruent to triangle ABC?
(1, 4)
(2, 5)
(5, 2)
(4, 1)
 one year ago
Nick plotted A(2, 2), B(3, 4), and C(4, 2) and joined the points to form triangle ABC. He plotted two other points at P(3, 4) and Q(2, 2). What should be the coordinates of the third point R to form triangle PQR that is congruent to triangle ABC? (1, 4) (2, 5) (5, 2) (4, 1)

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TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0@KonradZuse @AccessDenied

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Have you tried plotting the points that you were given?

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0Yes, but I still don't get it

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Could you post that graph here? :)

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0I actually wrote it on loose leaf paper lol. Soz

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0But how would you do it?

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1My first step is graphing the points. Then, I'd look for any obvious solutions like if there were symmetries between the points...

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0OK can I ask you a few more?

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Oh, I just realised something  the points have to correspond for the congruence! It's been a bit since I've done Geometry... lol. :P Let me graph it myself quick.

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0OK thank you lol no problem

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1PQ = AB QR = BC PR = AC

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0So it is either a or b

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1We could either do something like guess and check each point to see if it is the same, or maybe use some algebra and find the point which is a distance of BC from Q and a distance of AC from P

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0I got a. Is that right?

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1A) appears correct to me as well. :) For Geometry, if it weren't so obvious, we could use distance formula for some arbitrary point R(x,y) that meets those two distance conditions and solve that twovariable system. This one is pretty simple to "see" though.

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0I have a few more questions, if that's all right with you?

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1I think we'd get two solutions, one would be some sort of fraction or rational and (1,4) also.

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Sure, that's fine. :)

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0OK thank you so much Triangle PQR is similar to triangle ABC in the figure below. What is the perimeter of triangle ABC? 10.5 inches 39.9 inches 42.0 inches 60.65 inches

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0I got B, just checking my work.

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1How did you get B)?

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0Tell you the truth, I guessed, i'm confused on how to do it.

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Ah, okay. Well, we'd like to first find that one side length that we don't know on the triangle. Ratios of corresponding sides on similar triangles have to be the same, so this is one way to approach it. Set up this proportion of the sides: \( \displaystyle \frac{\text{AC}}{\text{PR}} = \frac{\text{AB}}{\text{PQ}} \) Notice how these are in fact corresponding sides; we can tell by which angles they are between, or just by position in the name of the triangles. \( \color{green}{\textbf{A}}\text{B}\color{green}{\textbf{C}} ~ \color{green}{\textbf{P}}\text{Q}\color{green}{\textbf{R}} \)

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1So, can you find the length of that side (AC) given this information?

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Correct. :) Now, we just sum the lengths of the sides.

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0Your VERY helpful, but I have alot more questions if that's all right with you. PS i'll medal you when we're all done, or now if you want.

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Hmm, how many questions? :)

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0Most of them are just checking though

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0Ok let's get started then lol. Jeremiah uses bamboo rods to make the frame of a tailless kite. He ties three bamboo rods together to form a right triangle PQR. He then ties another rod from P that meets RQ at a right angle. Segment PS in the figure below represents this rod and it is 4 inches long. Which of the following could be the lengths of segments QS and SR? QS = 2 inches, SR = 8 inches QS = 6 inches, SR = 10 inches QS = 2 inches, SR = 2 inches QS = 4 inches, SR = 12 inches

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0I got A. Is that correct?

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1If I recall this type of situation correctly: PS/ QS = RS/ PS 4 / QS = RS / 4 A) 4/2 = 8/4 ==> 2 = 2. Appears to be correct. :)

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0OK An architect planned to construct two similar stone pyramid structures in a park. The figure below shows the front view of the pyramids in her plan but there is an error in the dimensions. Which of the following changes should she make to the dimensions to correct her error? change the length of side AB to 2 feet change the length of side PQ to 8 feet change the length of side AB to 1 feet change the length of side PQ to 4 feet

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Hmm, do you have an answer to check?

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0No this one I don't quite understand.

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Ah, okay. This is another similar figures question. The key here is having the same side ratios again, similar to some earlier problems. First, I'd check each side ratio to see if there is a sort of "oddman out."

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Our corresponding sides: AC ~ PR, AB ~ PQ, BC ~ QR We should check all three of these ratios. AC/PR, AB/PQ, BC/QR

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0Ok i plugged in the numbers but now what?

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1What do you get for each ratio? Is one of them different?

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0ABPQ is the different on it gets 1/2, while all the other ratios get .3 repeated

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Yep. So, we'd like to find the solution that changes AB or PQ to match the other two side ratios.

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1For this, we could just go through each proposed solution and check to see if it works out.

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0Ok only 2 more left.

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0Joshua used two wood beams, PC and QA, to support the roof of a model house. The beams intersect each other to form two similar triangles QRP and ARC as shown in the figure below. The length of segment PR is 1.8 inches and the length of segment CR is 3.3inches. The distance between A and C is 6.6 inches. What is the distance between the endpoints of the beams P and Q? 3.6 inches 0.9 inches 1.8 inches 2.5 inches

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Here is another case of similar triangles. Can you identify the sideratios here? Just to see if you understand the similar triangles have side ratios detail. :)

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0Oh I forgot to trell you I got A.

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Ah, okay. A) is correct to me. :) We set up a simple side ratio: QR/PR = AC/PQ' 3.3/1.8 = 6.6/x; x = 6.6 * 1.8 / 3.3 = 3.6

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0Moris drew two triangles; triangle ABC and triangle PQR, on a coordinate grid. The coordinates of the vertices of triangle PQR are P(3, 2), Q(3, 4), and R(1, 4). The coordinates of the vertices of triangle ABC are A(3, 4), B(1, 4), C(3, 2). Which postulate can be used to prove that the two triangles are congruent? SAS, because AAA, because ASA, because SSS, because

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1Yeah, I am thinking D) as well. We're given all the points, we could easily just take distance formula or if they're horixontal/vertical, count.

TommyTrojan
 one year ago
Best ResponseYou've already chosen the best response.0Well I guess that's it, I have more but, since I only said 5 I will keep my word and let you go. OK Thanks though

AccessDenied
 one year ago
Best ResponseYou've already chosen the best response.1You're welcome! :)
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