anonymous
  • anonymous
help me please Algebra 1
Mathematics
jamiebookeater
  • jamiebookeater
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ghazi
  • ghazi
2\[(-2)^{-3*24}=(-2)^{72}\]
whpalmer4
  • whpalmer4
I think that should be \[(-m)^{-3}n\] Yes?
ghazi
  • ghazi
what exactly is your question, what are you supposed to find?

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whpalmer4
  • whpalmer4
First thing to remember is that \[x^{-m} = \frac{1}{x^m}\]If we rewrite the expression in that fashion, we get \[\frac{n}{(-m)^3} = \frac{-24}{(-2)^3}\]Can you evaluate that?
whpalmer4
  • whpalmer4
\[(-2)^3 = (-2)*(-2)*(-2)\]
ghazi
  • ghazi
well no
anonymous
  • anonymous
its negative though right?
anonymous
  • anonymous
its -3 right?
whpalmer4
  • whpalmer4
@ghazi what do you mean, "well no"?
anonymous
  • anonymous
he means its not -4
whpalmer4
  • whpalmer4
Did someone say it was? \[\frac{-24}{(-2)*(-2)*(-2)}\]What does the expression on the bottom equal?
ghazi
  • ghazi
its not -4 , its 4 ,if the explanation of @whpalmer4 is true and second i am not sure if that explanation is true, it would be great if you could take snapshot and post it here :D @carlenstar281
anonymous
  • anonymous
I cant but thank you for helping me :)
ghazi
  • ghazi
:) YW
whpalmer4
  • whpalmer4
Yes, all of my statements are true and correct. The answer is not 4.
anonymous
  • anonymous
are you sure i get 4?
whpalmer4
  • whpalmer4
What is -2 * -2 * -2?
ghazi
  • ghazi
\[\frac{ -24 }{ -2*-2*-2 }=\frac{ -24 }{ -8 }---> -A*-A*-A=-A\]
ghazi
  • ghazi
and \[\frac{ -24 }{ -8 }=\frac{ 24 }{ 8 }=3\] LOL
ghazi
  • ghazi
that was the silliest mistake i've ever done
anonymous
  • anonymous
sorry computer froze haha its okay i did that to still thanks for helping!
ghazi
  • ghazi
np :)
anonymous
  • anonymous
also thank you to @whpalmer4 as well haha
whpalmer4
  • whpalmer4
Another way of looking at this is \[\frac{-24}{(-1*2)^3} = \frac{-24}{(-1)^3*2^3}\]\(-1^n = -1, n\) odd so we have \[\frac{-24}{-1*2^3} = \frac{-24}{-8} = 3\]
whpalmer4
  • whpalmer4
We can factor out that -1 because \[(ab)^n = a^nb^n\]

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