help me please Algebra 1

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

help me please Algebra 1

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

2\[(-2)^{-3*24}=(-2)^{72}\]
I think that should be \[(-m)^{-3}n\] Yes?
what exactly is your question, what are you supposed to find?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

First thing to remember is that \[x^{-m} = \frac{1}{x^m}\]If we rewrite the expression in that fashion, we get \[\frac{n}{(-m)^3} = \frac{-24}{(-2)^3}\]Can you evaluate that?
\[(-2)^3 = (-2)*(-2)*(-2)\]
well no
its negative though right?
its -3 right?
@ghazi what do you mean, "well no"?
he means its not -4
Did someone say it was? \[\frac{-24}{(-2)*(-2)*(-2)}\]What does the expression on the bottom equal?
its not -4 , its 4 ,if the explanation of @whpalmer4 is true and second i am not sure if that explanation is true, it would be great if you could take snapshot and post it here :D @carlenstar281
I cant but thank you for helping me :)
:) YW
Yes, all of my statements are true and correct. The answer is not 4.
are you sure i get 4?
What is -2 * -2 * -2?
\[\frac{ -24 }{ -2*-2*-2 }=\frac{ -24 }{ -8 }---> -A*-A*-A=-A\]
and \[\frac{ -24 }{ -8 }=\frac{ 24 }{ 8 }=3\] LOL
that was the silliest mistake i've ever done
sorry computer froze haha its okay i did that to still thanks for helping!
np :)
also thank you to @whpalmer4 as well haha
Another way of looking at this is \[\frac{-24}{(-1*2)^3} = \frac{-24}{(-1)^3*2^3}\]\(-1^n = -1, n\) odd so we have \[\frac{-24}{-1*2^3} = \frac{-24}{-8} = 3\]
We can factor out that -1 because \[(ab)^n = a^nb^n\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question