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help me please Algebra 1

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I think that should be \[(-m)^{-3}n\] Yes?
what exactly is your question, what are you supposed to find?

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Other answers:

First thing to remember is that \[x^{-m} = \frac{1}{x^m}\]If we rewrite the expression in that fashion, we get \[\frac{n}{(-m)^3} = \frac{-24}{(-2)^3}\]Can you evaluate that?
\[(-2)^3 = (-2)*(-2)*(-2)\]
well no
its negative though right?
its -3 right?
@ghazi what do you mean, "well no"?
he means its not -4
Did someone say it was? \[\frac{-24}{(-2)*(-2)*(-2)}\]What does the expression on the bottom equal?
its not -4 , its 4 ,if the explanation of @whpalmer4 is true and second i am not sure if that explanation is true, it would be great if you could take snapshot and post it here :D @carlenstar281
I cant but thank you for helping me :)
:) YW
Yes, all of my statements are true and correct. The answer is not 4.
are you sure i get 4?
What is -2 * -2 * -2?
\[\frac{ -24 }{ -2*-2*-2 }=\frac{ -24 }{ -8 }---> -A*-A*-A=-A\]
and \[\frac{ -24 }{ -8 }=\frac{ 24 }{ 8 }=3\] LOL
that was the silliest mistake i've ever done
sorry computer froze haha its okay i did that to still thanks for helping!
np :)
also thank you to @whpalmer4 as well haha
Another way of looking at this is \[\frac{-24}{(-1*2)^3} = \frac{-24}{(-1)^3*2^3}\]\(-1^n = -1, n\) odd so we have \[\frac{-24}{-1*2^3} = \frac{-24}{-8} = 3\]
We can factor out that -1 because \[(ab)^n = a^nb^n\]

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