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carlenstar281

  • 2 years ago

help me please Algebra 1

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  1. ghazi
    • 2 years ago
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    2\[(-2)^{-3*24}=(-2)^{72}\]

  2. whpalmer4
    • 2 years ago
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    I think that should be \[(-m)^{-3}n\] Yes?

  3. ghazi
    • 2 years ago
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    what exactly is your question, what are you supposed to find?

  4. whpalmer4
    • 2 years ago
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    First thing to remember is that \[x^{-m} = \frac{1}{x^m}\]If we rewrite the expression in that fashion, we get \[\frac{n}{(-m)^3} = \frac{-24}{(-2)^3}\]Can you evaluate that?

  5. whpalmer4
    • 2 years ago
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    \[(-2)^3 = (-2)*(-2)*(-2)\]

  6. ghazi
    • 2 years ago
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    well no

  7. carlenstar281
    • 2 years ago
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    its negative though right?

  8. carlenstar281
    • 2 years ago
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    its -3 right?

  9. whpalmer4
    • 2 years ago
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    @ghazi what do you mean, "well no"?

  10. carlenstar281
    • 2 years ago
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    he means its not -4

  11. whpalmer4
    • 2 years ago
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    Did someone say it was? \[\frac{-24}{(-2)*(-2)*(-2)}\]What does the expression on the bottom equal?

  12. ghazi
    • 2 years ago
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    its not -4 , its 4 ,if the explanation of @whpalmer4 is true and second i am not sure if that explanation is true, it would be great if you could take snapshot and post it here :D @carlenstar281

  13. carlenstar281
    • 2 years ago
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    I cant but thank you for helping me :)

  14. ghazi
    • 2 years ago
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    :) YW

  15. whpalmer4
    • 2 years ago
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    Yes, all of my statements are true and correct. The answer is not 4.

  16. carlenstar281
    • 2 years ago
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    are you sure i get 4?

  17. whpalmer4
    • 2 years ago
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    What is -2 * -2 * -2?

  18. ghazi
    • 2 years ago
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    \[\frac{ -24 }{ -2*-2*-2 }=\frac{ -24 }{ -8 }---> -A*-A*-A=-A\]

  19. ghazi
    • 2 years ago
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    and \[\frac{ -24 }{ -8 }=\frac{ 24 }{ 8 }=3\] LOL

  20. ghazi
    • 2 years ago
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    that was the silliest mistake i've ever done

  21. carlenstar281
    • 2 years ago
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    sorry computer froze haha its okay i did that to still thanks for helping!

  22. ghazi
    • 2 years ago
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    np :)

  23. carlenstar281
    • 2 years ago
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    also thank you to @whpalmer4 as well haha

  24. whpalmer4
    • 2 years ago
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    Another way of looking at this is \[\frac{-24}{(-1*2)^3} = \frac{-24}{(-1)^3*2^3}\]\(-1^n = -1, n\) odd so we have \[\frac{-24}{-1*2^3} = \frac{-24}{-8} = 3\]

  25. whpalmer4
    • 2 years ago
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    We can factor out that -1 because \[(ab)^n = a^nb^n\]

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