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ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
\[0.2=\cos(\frac{ \pi t }{ 12 })\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
solve for t
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{\pi t}{12}=\arccos (0.2)\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
oopss i did not think this way thx
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
but are you allowed to use calculator \[\pi t/12=\pm \arccos(0.2)+2 \pi k,\forall k\in Z\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i got 5.231 but i only got one what about other value
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1359586504389:dw
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
notice that there are infinite number of solutiond but the general solution of these is \[\huge t=\frac{12}{\pi}\arccos(0.2)+2\pi k\] where k can be chosen from interger k={....2,1,0,1,2,3,4...}
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
where that +2 pi k came from
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
this is for every period of cos wich is every 360 =2pi but if you never did it just consider your answer + and 5.321 and 3605.321
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
but the answers are +5.321 and 18.767
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
first \[\frac{t \pi}{12}=\cos^{1}{0.2}=78\]
 one year ago
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