ksaimouli
  • ksaimouli
simplyfy
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ksaimouli
  • ksaimouli
\[0.2=\cos(\frac{ \pi t }{ 12 })\]
ksaimouli
  • ksaimouli
solve for t
anonymous
  • anonymous
\[\frac{\pi t}{12}=\arccos (0.2)\]

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ksaimouli
  • ksaimouli
oopss i did not think this way thx
anonymous
  • anonymous
but are you allowed to use calculator \[\pi t/12=\pm \arccos(0.2)+2 \pi k,\forall k\in Z\]
ksaimouli
  • ksaimouli
i got 5.231 but i only got one what about other value
ksaimouli
  • ksaimouli
|dw:1359586504389:dw|
ksaimouli
  • ksaimouli
@Jonask
anonymous
  • anonymous
notice that there are infinite number of solutiond but the general solution of these is \[\huge t=\frac{12}{\pi}\arccos(0.2)+2\pi k\] where k can be chosen from interger k={....-2,-1,0,1,2,3,4...}
ksaimouli
  • ksaimouli
where that +2 pi k came from
anonymous
  • anonymous
this is for every period of cos wich is every 360 =2pi but if you never did it just consider your answer + and -5.321 and 360-5.321
ksaimouli
  • ksaimouli
but the answers are +5.321 and 18.767
anonymous
  • anonymous
first \[\frac{t \pi}{12}=\cos^{-1}{0.2}=78\]

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