A community for students.
Here's the question you clicked on:
 0 viewing
ksaimouli
 3 years ago
simplyfy
ksaimouli
 3 years ago
simplyfy

This Question is Closed

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0\[0.2=\cos(\frac{ \pi t }{ 12 })\]

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{\pi t}{12}=\arccos (0.2)\]

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0oopss i did not think this way thx

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.1but are you allowed to use calculator \[\pi t/12=\pm \arccos(0.2)+2 \pi k,\forall k\in Z\]

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0i got 5.231 but i only got one what about other value

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359586504389:dw

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.1notice that there are infinite number of solutiond but the general solution of these is \[\huge t=\frac{12}{\pi}\arccos(0.2)+2\pi k\] where k can be chosen from interger k={....2,1,0,1,2,3,4...}

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0where that +2 pi k came from

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.1this is for every period of cos wich is every 360 =2pi but if you never did it just consider your answer + and 5.321 and 3605.321

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0but the answers are +5.321 and 18.767

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.1first \[\frac{t \pi}{12}=\cos^{1}{0.2}=78\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.