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Which ones?! Which of the following ordered pairs is not a solution to the inequality y ≥ -4x - 2? A1) (-1, 0) B1) (0, 0) C1) (4, 4) D1) (1, 3) ---- Which of the following ordered pairs is a solution to the inequality y ≥ 4x - 2? A2) (0, -4) B2) (0, 0) C2) (0, -3) D2) (0, -5)

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y ≥ -4x - 2 C1) (4, 4) Put in the x-coordinate (-1) for x and put in the y-coordinate (0) for y. If the inequality is true, then it's a solution. Is 4 ≥ -4(4) - 2? 0 ≥ -16 - 2 0 ≥ -18 That statement is true, so (4, 4) is a solution. Do the same with the other ordered pairs in both problems.
I have trouble with that kind of stuff..... I'm really really bad at math
Can you follow my example above for choice C1? Try now cgoice A!, (-1, 0). Insert -1 for x and 0 for y, and see if it makes a true statement.

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Other answers:

0 ≥ -4(-1) - 2
0 ≥ -4 - 2 0 ≥ -6
So it's D1?
(-4)(-1) = 4 When you multiply or divide numbers, two positives or two negatives make a positive. A negative and a positive make a negative.
0 ≥ 4 - 2 0 ≥ 2 So it's A1?
And B2?
I got full points for both guesses! Thank you so much! (A1 and B2)

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