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Gungirl4ever1994

  • 3 years ago

P^2-4p-32/p+4 @ghazi –p + 8; p ≠ –4 p – 8; p ≠ –4 –p – 8; p ≠ –4 p + 8; p ≠ –4

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  1. ghazi
    • 3 years ago
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    well \[P^2-4p-32=(p-8)(p+4)\]

  2. ghazi
    • 3 years ago
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    \[\frac{ (p-8)(p+4) }{ (p+4) }=(p-8)\] p=/ 4

  3. Gungirl4ever1994
    • 3 years ago
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    confused

  4. ghazi
    • 3 years ago
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    @Gungirl4ever1994 clear?

  5. Gungirl4ever1994
    • 3 years ago
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    i no =/4 bc thats at the end of em all

  6. ghazi
    • 3 years ago
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    sorry \[p \ne 4\]

  7. ghazi
    • 3 years ago
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    b

  8. Gungirl4ever1994
    • 3 years ago
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    bubba help on more?

  9. ghazi
    • 3 years ago
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    keep posting :)

  10. Gungirl4ever1994
    • 3 years ago
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  11. Gungirl4ever1994
    • 3 years ago
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    ???

  12. ghazi
    • 3 years ago
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    \[\frac{ q^2+11q+24 }{ q^2-5q-24 } =\frac{ (q+8)(q+3) }{ (q-8)(q+3) }=\frac{ (q+8) }{ (q-8) }\]

  13. ghazi
    • 3 years ago
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    C

  14. Gungirl4ever1994
    • 3 years ago
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  15. ghazi
    • 3 years ago
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    you can do this one :) you need to factorize

  16. Gungirl4ever1994
    • 3 years ago
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    plzzz

  17. ghazi
    • 3 years ago
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    yes you can do it :D z^2+3z+2=(z+2)(z+1)

  18. ghazi
    • 3 years ago
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    A

  19. Gungirl4ever1994
    • 3 years ago
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    thanks talk to you in a bit :)

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