Gungirl4ever1994
P^24p32/p+4
@ghazi
–p + 8; p ≠ –4
p – 8; p ≠ –4
–p – 8; p ≠ –4
p + 8; p ≠ –4



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ghazi
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well \[P^24p32=(p8)(p+4)\]

ghazi
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\[\frac{ (p8)(p+4) }{ (p+4) }=(p8)\] p=/ 4

Gungirl4ever1994
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confused

ghazi
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@Gungirl4ever1994 clear?

Gungirl4ever1994
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i no =/4
bc thats at the end of em all

ghazi
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sorry \[p \ne 4\]

ghazi
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b

Gungirl4ever1994
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bubba help on more?

ghazi
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keep posting :)



ghazi
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\[\frac{ q^2+11q+24 }{ q^25q24 } =\frac{ (q+8)(q+3) }{ (q8)(q+3) }=\frac{ (q+8) }{ (q8) }\]

ghazi
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C


ghazi
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you can do this one :) you need to factorize


ghazi
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yes you can do it :D z^2+3z+2=(z+2)(z+1)

ghazi
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A

Gungirl4ever1994
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thanks talk to you in a bit :)