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patty_1CE

  • one year ago

dy/dx = x+y/y-x' , y(1)=2 @zepdrix

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  1. TuringTest
    • one year ago
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    x'=dx/dy ??

  2. patty_1CE
    • one year ago
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    i got a couple steps in and lost it

  3. TuringTest
    • one year ago
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    I am asking you, what does x' represents here? or is that a typo?

  4. patty_1CE
    • one year ago
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    it represents x prime

  5. zepdrix
    • one year ago
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    That doesn't make sense patty :c

  6. zepdrix
    • one year ago
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    The prime would suggest it's a `derivative of x`. Derivative with respect to what other variable? With respect to y? So it does represent dx/dy?

  7. zepdrix
    • one year ago
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    Or that's all the info you were given? c:

  8. patty_1CE
    • one year ago
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    screw x prime and say the ' was a typo

  9. zepdrix
    • one year ago
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    lol XD

  10. patty_1CE
    • one year ago
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    z anything?

  11. TuringTest
    • one year ago
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    let v=y-x then v'=y'-1 -> y'=v'+1 we then have v'+1=(v+2x)/v try solving that, then subbing back in for v in terms of y after integration

  12. patty_1CE
    • one year ago
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    i think i did something wrong

  13. TuringTest
    • one year ago
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    can you try to show some of what you did?

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