patty_1CE
dy/dx = x+y/yx' , y(1)=2
@zepdrix



This Question is Closed

TuringTest
Best Response
You've already chosen the best response.
0
x'=dx/dy ??

patty_1CE
Best Response
You've already chosen the best response.
0
i got a couple steps in and lost it

TuringTest
Best Response
You've already chosen the best response.
0
I am asking you, what does x' represents here? or is that a typo?

patty_1CE
Best Response
You've already chosen the best response.
0
it represents x prime

zepdrix
Best Response
You've already chosen the best response.
0
That doesn't make sense patty :c

zepdrix
Best Response
You've already chosen the best response.
0
The prime would suggest it's a `derivative of x`.
Derivative with respect to what other variable?
With respect to y?
So it does represent dx/dy?

zepdrix
Best Response
You've already chosen the best response.
0
Or that's all the info you were given? c:

patty_1CE
Best Response
You've already chosen the best response.
0
screw x prime and say the ' was a typo

zepdrix
Best Response
You've already chosen the best response.
0
lol XD

patty_1CE
Best Response
You've already chosen the best response.
0
z anything?

TuringTest
Best Response
You've already chosen the best response.
0
let v=yx
then v'=y'1 > y'=v'+1
we then have
v'+1=(v+2x)/v
try solving that, then subbing back in for v in terms of y after integration

patty_1CE
Best Response
You've already chosen the best response.
0
i think i did something wrong

TuringTest
Best Response
You've already chosen the best response.
0
can you try to show some of what you did?