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TuringTest Group TitleBest ResponseYou've already chosen the best response.0
x'=dx/dy ??
 one year ago

patty_1CE Group TitleBest ResponseYou've already chosen the best response.0
i got a couple steps in and lost it
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
I am asking you, what does x' represents here? or is that a typo?
 one year ago

patty_1CE Group TitleBest ResponseYou've already chosen the best response.0
it represents x prime
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
That doesn't make sense patty :c
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
The prime would suggest it's a `derivative of x`. Derivative with respect to what other variable? With respect to y? So it does represent dx/dy?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Or that's all the info you were given? c:
 one year ago

patty_1CE Group TitleBest ResponseYou've already chosen the best response.0
screw x prime and say the ' was a typo
 one year ago

patty_1CE Group TitleBest ResponseYou've already chosen the best response.0
z anything?
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
let v=yx then v'=y'1 > y'=v'+1 we then have v'+1=(v+2x)/v try solving that, then subbing back in for v in terms of y after integration
 one year ago

patty_1CE Group TitleBest ResponseYou've already chosen the best response.0
i think i did something wrong
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
can you try to show some of what you did?
 one year ago
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