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This is a linear equation and can be solved with an integrating factor. Do you know how to use that technique?
weve gone over them in class however what we do in class seems much easier than on the homework..
I have to eat dinner. In the meantime, use this to try to figure out the integrating factor, mu.

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oops http://tutorial.math.lamar.edu/Classes/DE/Linear.aspx
Hi friend, I just give the idea for you to consider, you have the equation as x y' + 3y = 4x you should change a little bit as xy' + 3y - 4x =0. it looks like the formula to figure out characteristic equation with the variable is y and its derivative. Don't take x as variable as usual. take it as a number and solve for y. since you have y(0) =0, try my way. (I'm taking discrete math, not master enough to give out the whole thing but i can see it is characteristic equation form
took discrete. it was hard. bu this is a whole new level of math. i can see where your talking about and gave it a though however im gnna need an integrating factor, just gotta figure out which one
thank you, I am waiting for the solution from others. I need it too. for my math classes. If you know how to solve it, post it please
first step: get the coefficient of y' to be 1 so divide both sides by x y'+3y/x=4 the integrating factor is then\[\large\mu(x)=e^{\int\frac{dx}x}\]

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