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Four particles at the corners of a square with a side length L = 2m are connected by massless rods (See below) The particle masses are\( m_1 = m_4 = 3\) kg and \( m_2 = m_3 = 4\) kg. Find the moment of inertia of the system about the z axis.

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\[I = \sum_{i=1}^{n}mi.(ri)^2\]
The trick here is to Choose Orgin..Make Mass ( M3) as Orgin.

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Other answers:

Wait..... I about Z I(z) = I (x) + I (y)
so r for m3 is zero?
Sorry, im confused.
and r for m1 and m4 is L? L√2 for m2, right?
Yes...u r right..)
Hmm, I tried this way and i was wrong, guess i should tr again... the key answer is 56 kg*m², by the way.
I got it. Thanks.
glad u did it

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