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geerky42

  • 2 years ago

Four particles at the corners of a square with a side length L = 2m are connected by massless rods (See below) The particle masses are\( m_1 = m_4 = 3\) kg and \( m_2 = m_3 = 4\) kg. Find the moment of inertia of the system about the z axis.

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  1. geerky42
    • 2 years ago
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    |dw:1359596705890:dw|

  2. Yahoo!
    • 2 years ago
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    \[I = \sum_{i=1}^{n}mi.(ri)^2\]

  3. Yahoo!
    • 2 years ago
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    The trick here is to Choose Orgin..Make Mass ( M3) as Orgin.

  4. Yahoo!
    • 2 years ago
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    Wait..... I about Z I(z) = I (x) + I (y)

  5. geerky42
    • 2 years ago
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    so r for m3 is zero?

  6. geerky42
    • 2 years ago
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    Sorry, im confused.

  7. Yahoo!
    • 2 years ago
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    Yup..

  8. geerky42
    • 2 years ago
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    and r for m1 and m4 is L? L√2 for m2, right?

  9. Yahoo!
    • 2 years ago
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    Yes...u r right..)

  10. geerky42
    • 2 years ago
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    Hmm, I tried this way and i was wrong, guess i should tr again... the key answer is 56 kg*m², by the way.

  11. geerky42
    • 2 years ago
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    try*

  12. geerky42
    • 2 years ago
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    I got it. Thanks.

  13. Yahoo!
    • 2 years ago
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    glad u did it

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