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anonymous
 3 years ago
limit help
anonymous
 3 years ago
limit help

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 1}\frac{ x1 }{ \sqrt[3]{x+7}2 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I am having trouble with this equation we are given the hint make the substation x+7=t^3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Rationalise the denominator by multiplying by \[\frac{ \sqrt[3]{(x+7)^2}+2 }{ \sqrt[3]{(x+7)^2}+2 } \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh now you say you were given that.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[=\frac{ t^371 }{ t2 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0x+7=t^3 as x > 1 t > 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And you can get rid of the denominator. Once you do that. Sub back the x's.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so when i make the sub I get \[\lim_{x \rightarrow 1} \frac{ x1 }{ t+2 }\] ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No you sub the x on the numerator as well.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0a^3  b^3 = (ab) (a^2 +ab + b^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[t^3=x+7\] make x the subject. \[x=t^37\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now sub the x on the numerator with t^37

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh now i get it. pass the duh stamp

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now you can get rid of that denominator.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Once you do that, remember to replace the t's with \[\sqrt[3]{x+7}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and then you can then sub in x=1 to find the limit.
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