Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

adam32885

  • 3 years ago

limit help

  • This Question is Closed
  1. perl
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    whats the question>

  2. adam32885
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\lim_{x \rightarrow 1}\frac{ x-1 }{ \sqrt[3]{x+7}-2 }\]

  3. adam32885
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I am having trouble with this equation we are given the hint make the substation x+7=t^3

  4. Azteck
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Rationalise the denominator by multiplying by \[\frac{ \sqrt[3]{(x+7)^2}+2 }{ \sqrt[3]{(x+7)^2}+2 } \]

  5. Azteck
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Oh now you say you were given that.

  6. Azteck
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    \[=\frac{ t^3-7-1 }{ t-2 }\]

  7. Yahoo!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    x+7=t^3 as x ---> 1 t ----> 2

  8. Azteck
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Factorise

  9. Azteck
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    And you can get rid of the denominator. Once you do that. Sub back the x's.

  10. adam32885
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so when i make the sub I get \[\lim_{x \rightarrow 1} \frac{ x-1 }{ t+2 }\] ?

  11. Azteck
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    No you sub the x on the numerator as well.

  12. Yahoo!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    a^3 - b^3 = (a-b) (a^2 +ab + b^2

  13. Azteck
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    \[t^3=x+7\] make x the subject. \[x=t^3-7\]

  14. Azteck
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Now sub the x on the numerator with t^3-7

  15. adam32885
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh now i get it. pass the duh stamp

  16. Azteck
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Now you can get rid of that denominator.

  17. Azteck
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Once you do that, remember to replace the t's with \[\sqrt[3]{x+7}\]

  18. Azteck
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    and then you can then sub in x=1 to find the limit.

  19. adam32885
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    got it thank you!

  20. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy