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The displacement vectors A and B both have magnitudes of 3.30 m. The direction of vector A is 16.6 degrees.
Find the magnitude of A+B, AB, BA, and A2B graphically.
PLEASE HELP ;/
 one year ago
 one year ago
The displacement vectors A and B both have magnitudes of 3.30 m. The direction of vector A is 16.6 degrees. Find the magnitude of A+B, AB, BA, and A2B graphically. PLEASE HELP ;/
 one year ago
 one year ago

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Outkast3r09Best ResponseYou've already chosen the best response.0
each vector has a y and x component
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
well you're given a magnitude
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
dw:1359604762762:dw
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
dw:1359605259789:dw
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
yeah, im here.. trying to understand
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
dw:1359605406061:dw these need direction due to vectors .. it says A direction is 16.6 degrees sooooo
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
dw:1359605476238:dw
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
so in order to make sense of each vector you need to break them down into right triangles that show components of x and y i'll start with Adw:1359605592468:dw
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
now using trig functions you can find the components correct ? can you do that?
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
using sohcahtoa right?
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
i got 3.16 as side A_y..
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
so now we have \[A_x=Acos(16.6)\] \[A_y=Asin(16.6)\]
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
you had them switched around =]
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
and 0.95 as a_y.. A=3.30 right?
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
yep sounds correct
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
atleast according to my diagram lol
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
alright so the B is easy since there is only one component to it... which is the \[B_y\]
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
B=3.30 but theres no theta?
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
yes but it's a simple line on the y axis so it only has one component an x is what i meant =/
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
so you have \[B_x=3.30\]
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
dw:1359606759899:dw
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
now you just add the like components to get 2 sides and the magnitude will be the square root of those squared total components
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
"like components" ? 8.1?
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
so B is 3.30 and for A do I add a_x and a_y and A?
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
well lets do it like my book says \[R_x=A_x+B_x\] \[R_y=A_y+B_y\]
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
\[A+B=\sqrt{R_x^2+R_y^2}\]
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
dw:1359607102751:dw
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
\[B_x=3.30\] \[A_x=3.30cos(16.6)\] \[A_y=3.30sin(16.6)\]
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
\[R_x=6.46\] \[R_y=.943\] \[R=\sqrt{6.46^2+.943^2}\]
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
6.53 to be more exact
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
yeah i got that too now. i rounded wrong earlier.
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
so for AB would i just subtract?
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
yes to do it easily i'm trying to remember what it looks like loldw:1359607683207:dw
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
ab is the diagonal from left to right if i remember right so you have to take A and move it infront of b like this
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
dw:1359607791579:dw
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
oh my lordy... i give up... ;/ my grade is good enough.. 96.3% on this assignment. I'm done with this question.. i still have to do a lab report and study for calc 2... thanks for the help though ;/
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
I'll go back later when i have more imte tomorrow and try to figure it out lol.
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
i looked at my book you have to face the vectors in certain ways so ab says to face the vecotrs inward to eachother \
 one year ago
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