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 one year ago
The displacement vectors A and B both have magnitudes of 3.30 m. The direction of vector A is 16.6 degrees.
Find the magnitude of A+B, AB, BA, and A2B graphically.
PLEASE HELP ;/
 one year ago
The displacement vectors A and B both have magnitudes of 3.30 m. The direction of vector A is 16.6 degrees. Find the magnitude of A+B, AB, BA, and A2B graphically. PLEASE HELP ;/

This Question is Closed

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0each vector has a y and x component

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0well you're given a magnitude

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359604762762:dw

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359605259789:dw

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0yeah, im here.. trying to understand

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359605406061:dw these need direction due to vectors .. it says A direction is 16.6 degrees sooooo

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359605476238:dw

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0so in order to make sense of each vector you need to break them down into right triangles that show components of x and y i'll start with Adw:1359605592468:dw

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0now using trig functions you can find the components correct ? can you do that?

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0using sohcahtoa right?

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0i got 3.16 as side A_y..

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0so now we have \[A_x=Acos(16.6)\] \[A_y=Asin(16.6)\]

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0you had them switched around =]

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0and 0.95 as a_y.. A=3.30 right?

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0yep sounds correct

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0atleast according to my diagram lol

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0alright so the B is easy since there is only one component to it... which is the \[B_y\]

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0B=3.30 but theres no theta?

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0yes but it's a simple line on the y axis so it only has one component an x is what i meant =/

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0so you have \[B_x=3.30\]

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359606759899:dw

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0now you just add the like components to get 2 sides and the magnitude will be the square root of those squared total components

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0"like components" ? 8.1?

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0so B is 3.30 and for A do I add a_x and a_y and A?

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0well lets do it like my book says \[R_x=A_x+B_x\] \[R_y=A_y+B_y\]

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0\[A+B=\sqrt{R_x^2+R_y^2}\]

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359607102751:dw

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0\[B_x=3.30\] \[A_x=3.30cos(16.6)\] \[A_y=3.30sin(16.6)\]

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0\[R_x=6.46\] \[R_y=.943\] \[R=\sqrt{6.46^2+.943^2}\]

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.06.53 to be more exact

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0yeah i got that too now. i rounded wrong earlier.

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0so for AB would i just subtract?

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0yes to do it easily i'm trying to remember what it looks like loldw:1359607683207:dw

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0ab is the diagonal from left to right if i remember right so you have to take A and move it infront of b like this

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359607791579:dw

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0oh my lordy... i give up... ;/ my grade is good enough.. 96.3% on this assignment. I'm done with this question.. i still have to do a lab report and study for calc 2... thanks for the help though ;/

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0I'll go back later when i have more imte tomorrow and try to figure it out lol.

Outkast3r09
 one year ago
Best ResponseYou've already chosen the best response.0i looked at my book you have to face the vectors in certain ways so ab says to face the vecotrs inward to eachother \
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