At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
there is no smallest integer
so they are all true
So it would none of the above?
if you are doing if then -> -p ^ q
@What is the problem being modeled? x appears to be 156 on what was posted but what is the scenario of the problem that calls for the smallest x? @kitsune0724
they are all true
The question just says if x is the smallest integer, which of the equations models the problem. The choices are: 4x=636, x(x+2)(x+4)(x+6)=636, x+(x+2)+(x+4)+(x+6)=636, x+(x+2)+(x+4)+(x+6)=636 and none of the above. I got the third choice. @Directix
@kitsune0724 I assume that we have to solve all the equations for x and then choose as the answer the equation which yields the smallest value of x of all options. Let me check your answer.
@kitsune0724 In the options, I think you wrote one of them twice: x+(x+2)+(x+4)+(x+6)=636, x+(x+2)+(x+4)+(x+6)=636. What is supposed to be there?
how is there a smallest integer? I think this is a question about if then....which is -P v Q thus since P is false the statement is true for what follows...
Something bothers me about this problem. The question asks the following: " which of the equations **models the problem.** @kitsune0724 --> What problem?
yes. it's suppose to be there. @Directrix
That's all it says in the problem.
plewase tell me why you guys are ignoring the smallest integer part? and my explination...
I'm not ignoring your explanation @zzr0ck3r but that's not one of the choices.
hehe, they are all true is the choice:)
@zzr0ck3r -P v Q thus since P is false the statement is true for what follows... I am not commenting on your contributions because I do not follow what they have to do with the problem. And, I STILL do not think we have been given the entire problem. My best guess is that there's a given problem about consecutive integers and we are to select the equation that can be used to solve that problem. Yet, I cannot find out from @kitsune0724 what that problem is.
There's no problem given @Directrix. I'm sorry.
@kitsune0724 Why did you pick the third choice? And, I know two of the choices cannot be identical. So, there's something faulty about this problem. I cannot help without more information. The choices are: ... SAME x+(x+2)+(x+4)+(x+6)=636, SAME x+(x+2)+(x+4)+(x+6)=636 ....
@kitsune0724 I'm going to try to get a fresh pair of eyes for this problem. Hold on.
@Directrix it says if x is the smallest integer then .... thus P = x is the smallest integer this is never true^^^^^^ thus we have ~P which implies Q is true for any Q. we have 4 Q's
@saifoo.khan --> We need a fresh pair of eyes on this problem. Would you render your thoughts, please? Thanks.
I dont see why you would try and solve a problem that cant be solved..... if x is an irrational rational number what is x^2 <----would you try and solve this?
I don't really get the question. Sorry. :/ Are you sure it's complete? @kitsune0724
Thank y'all for your help.
Glad to try to help. It was a mathematical adventure. :)