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kitsune0724
If x is the smallest integer, which of the following equations models the problem? I got X+(x+2)+(x+4)+(x+6)=636. Is this correct? Please and thank you.
there is no smallest integer
So it would none of the above?
if you are doing if then -> -p ^ q
@What is the problem being modeled? x appears to be 156 on what was posted but what is the scenario of the problem that calls for the smallest x? @kitsune0724
The question just says if x is the smallest integer, which of the equations models the problem. The choices are: 4x=636, x(x+2)(x+4)(x+6)=636, x+(x+2)+(x+4)+(x+6)=636, x+(x+2)+(x+4)+(x+6)=636 and none of the above. I got the third choice. @Directix
@kitsune0724 I assume that we have to solve all the equations for x and then choose as the answer the equation which yields the smallest value of x of all options. Let me check your answer.
@kitsune0724 In the options, I think you wrote one of them twice: x+(x+2)+(x+4)+(x+6)=636, x+(x+2)+(x+4)+(x+6)=636. What is supposed to be there?
how is there a smallest integer? I think this is a question about if then....which is -P v Q thus since P is false the statement is true for what follows...
Something bothers me about this problem. The question asks the following: " which of the equations **models the problem.** @kitsune0724 --> What problem?
yes. it's suppose to be there. @Directrix
That's all it says in the problem.
plewase tell me why you guys are ignoring the smallest integer part? and my explination...
I'm not ignoring your explanation @zzr0ck3r but that's not one of the choices.
hehe, they are all true is the choice:)
@zzr0ck3r -P v Q thus since P is false the statement is true for what follows... I am not commenting on your contributions because I do not follow what they have to do with the problem. And, I STILL do not think we have been given the entire problem. My best guess is that there's a given problem about consecutive integers and we are to select the equation that can be used to solve that problem. Yet, I cannot find out from @kitsune0724 what that problem is.
There's no problem given @Directrix. I'm sorry.
@kitsune0724 Why did you pick the third choice? And, I know two of the choices cannot be identical. So, there's something faulty about this problem. I cannot help without more information. The choices are: ... SAME x+(x+2)+(x+4)+(x+6)=636, SAME x+(x+2)+(x+4)+(x+6)=636 ....
@kitsune0724 I'm going to try to get a fresh pair of eyes for this problem. Hold on.
@Directrix it says if x is the smallest integer then .... thus P = x is the smallest integer this is never true^^^^^^ thus we have ~P which implies Q is true for any Q. we have 4 Q's
@saifoo.khan --> We need a fresh pair of eyes on this problem. Would you render your thoughts, please? Thanks.
I dont see why you would try and solve a problem that cant be solved..... if x is an irrational rational number what is x^2 <----would you try and solve this?
I don't really get the question. Sorry. :/ Are you sure it's complete? @kitsune0724
Thank y'all for your help.
Glad to try to help. It was a mathematical adventure. :)