Here's the question you clicked on:
Haruko_03
(2x+5)(x^2+2x-10)=0
equate each term in bracket to 0
you can solve it like this... All I did was divide the 2 from the 10 and got 5 then replaced x with 5 and got the answer of 5 after doing the math. x^2-2x-10=5 5^2-2(5)-10=5 25-2(5)-10=5 25-10-10=5 15-10=5