A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
Set up an intergal for the colume of the solid obtained by ratating the region bounded by the parabolas
x=8y2y^2, x= 4yy^2
about the xaxis.
 one year ago
Set up an intergal for the colume of the solid obtained by ratating the region bounded by the parabolas x=8y2y^2, x= 4yy^2 about the xaxis.

This Question is Closed

Dido525
 one year ago
Best ResponseYou've already chosen the best response.0I have no idea how to do this :( .

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.3The maximum xvalue for each is at y = 2. The intersections of the two are at (0,0) and (0,4). Would you like to chop it up into 3 pieces or simply apply Pappus' Theorem?

Dido525
 one year ago
Best ResponseYou've already chosen the best response.0I can't use Pappus' theorem.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.3Why not? Specifically proscribed? Not yet presented? Or just not able?

Dido525
 one year ago
Best ResponseYou've already chosen the best response.0First of all, I need to sketch this thing. I can't figure out how the thing looks like.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.3Think it up yourself and surprise everyone! 3 pieces then. 1) Biggest Piece x from 4 to 8 and y from \(2  \sqrt{\dfrac{8x}{2}}\) to \(2 + \sqrt{\dfrac{8x}{2}}\) 2) Top Piece x from 0 to 4 and y from \(2 + \sqrt{4x}\) to \(2 + \sqrt{\dfrac{8x}{2}}\) 3) Bottom Piece x from 0 to 4 and y from \(2  \sqrt{\dfrac{8x}{2}}\) to \(2 + \sqrt{4x}\) Go!

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.3Why not flip it around to where you are more familiar and solve that problem. y = 8x2x^2 and y= 4xx^2 and wrap it around the yaxis!

Dido525
 one year ago
Best ResponseYou've already chosen the best response.0But that changes the entire question.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.3No. The question is to calculate the volume. Unique answers do not care how you find them. It MUST be considered a valid methodology.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.3Anyway, you can flip it around just to get a look at it, if you can't relate to the present condition.

Dido525
 one year ago
Best ResponseYou've already chosen the best response.0But if you switch the x and y's that should change the entire shape of the graph.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.3That's silly. Why would you think that? Absolutely not the case. It is the EXACT SAME problem.

Dido525
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359609779642:dw Something like that? REALLY bad sketch though.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.3dw:1359609887178:dw A little better. You crossed the xaxis. That's no good.

Dido525
 one year ago
Best ResponseYou've already chosen the best response.0yeah I know. I felt lazy.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.3Well, go ahead and do it, then. I gave you all the limits up above. Good luck. gtg
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.