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ddiez
Group Title
Algebra 2 help:
Solve. Check for extraneous solutions.
(√5x)  √x = 1
Also, "5x" is all under a radicand
I have an idea of what to do to solve it, but if someone could walk me through it that would be awesome (final answer is 1 [according to key])
 one year ago
 one year ago
ddiez Group Title
Algebra 2 help: Solve. Check for extraneous solutions. (√5x)  √x = 1 Also, "5x" is all under a radicand I have an idea of what to do to solve it, but if someone could walk me through it that would be awesome (final answer is 1 [according to key])
 one year ago
 one year ago

This Question is Closed

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
sqrt(5x) = 1 + sqrt(x) take square on both sides: 5x = (1+sqrt(x)) ^2 5  x = (1+sqrtx)(1+sqrtx) 5  x = 1 + 2sqrt(x) + x 5  2x  1 = 2sqrt x (4  2x) / 2 = sqrt x 2  x = sqrt x Taking square on both sides: (2x)^2 = (sqrt x)^2 (2x)^2 = x
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
Now solve this and you'll get 2 valuse..
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
values*
 one year ago
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