A community for students.
Here's the question you clicked on:
 0 viewing
ddiez
 3 years ago
Algebra 2 help:
Solve. Check for extraneous solutions.
(√5x)  √x = 1
Also, "5x" is all under a radicand
I have an idea of what to do to solve it, but if someone could walk me through it that would be awesome (final answer is 1 [according to key])
ddiez
 3 years ago
Algebra 2 help: Solve. Check for extraneous solutions. (√5x)  √x = 1 Also, "5x" is all under a radicand I have an idea of what to do to solve it, but if someone could walk me through it that would be awesome (final answer is 1 [according to key])

This Question is Closed

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.1sqrt(5x) = 1 + sqrt(x) take square on both sides: 5x = (1+sqrt(x)) ^2 5  x = (1+sqrtx)(1+sqrtx) 5  x = 1 + 2sqrt(x) + x 5  2x  1 = 2sqrt x (4  2x) / 2 = sqrt x 2  x = sqrt x Taking square on both sides: (2x)^2 = (sqrt x)^2 (2x)^2 = x

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.1Now solve this and you'll get 2 valuse..
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.