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toadytica305

  • 2 years ago

How do you solve when you have logs on one side but not the other? (2 problems inside)

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  1. toadytica305
    • 2 years ago
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  2. mathg8
    • 2 years ago
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    use the product rule log A + log B = log (AB)

  3. toadytica305
    • 2 years ago
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    I tried that... for Log x + log (x+15) = 2 I have (Log x)(log (x+15)) =2 i dont know what to do after The answer is 5

  4. saifoo.khan
    • 2 years ago
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    \[\lg x(x+15) = 2\]

  5. RadEn
    • 2 years ago
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    convert 2 to log 100

  6. AravindG
    • 2 years ago
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    log x+log (x+15)=log(x(x+15))!!

  7. RadEn
    • 2 years ago
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    it just a hint, so that both sides have log's :)

  8. toadytica305
    • 2 years ago
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    But how do you go from log(x(x+15)=2.. to x=5? I can't get that part

  9. RadEn
    • 2 years ago
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    log(x(x+15))=2 log(x(x+15)=log100 cancel out the log, giving us : x(x+15)=100 or x^2+15x-100=0 solve for x by factorization or by complete square or by quadratic formula

  10. RadEn
    • 2 years ago
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    got it ?

  11. toadytica305
    • 2 years ago
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    Yes! Just solved it.. thank you!

  12. RadEn
    • 2 years ago
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    yw

  13. toadytica305
    • 2 years ago
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    I didn't think of doing log 100 to cancel the logs on both sides

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