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toadytica305 Group Title

How do you solve when you have logs on one side but not the other? (2 problems inside)

  • one year ago
  • one year ago

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  1. toadytica305 Group Title
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    • one year ago
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  2. mathg8 Group Title
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    use the product rule log A + log B = log (AB)

    • one year ago
  3. toadytica305 Group Title
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    I tried that... for Log x + log (x+15) = 2 I have (Log x)(log (x+15)) =2 i dont know what to do after The answer is 5

    • one year ago
  4. saifoo.khan Group Title
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    \[\lg x(x+15) = 2\]

    • one year ago
  5. RadEn Group Title
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    convert 2 to log 100

    • one year ago
  6. AravindG Group Title
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    log x+log (x+15)=log(x(x+15))!!

    • one year ago
  7. RadEn Group Title
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    it just a hint, so that both sides have log's :)

    • one year ago
  8. toadytica305 Group Title
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    But how do you go from log(x(x+15)=2.. to x=5? I can't get that part

    • one year ago
  9. RadEn Group Title
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    log(x(x+15))=2 log(x(x+15)=log100 cancel out the log, giving us : x(x+15)=100 or x^2+15x-100=0 solve for x by factorization or by complete square or by quadratic formula

    • one year ago
  10. RadEn Group Title
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    got it ?

    • one year ago
  11. toadytica305 Group Title
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    Yes! Just solved it.. thank you!

    • one year ago
  12. RadEn Group Title
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    yw

    • one year ago
  13. toadytica305 Group Title
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    I didn't think of doing log 100 to cancel the logs on both sides

    • one year ago
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