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How do you solve when you have logs on one side but not the other? (2 problems inside)

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2 Attachments
use the product rule log A + log B = log (AB)
I tried that... for Log x + log (x+15) = 2 I have (Log x)(log (x+15)) =2 i dont know what to do after The answer is 5

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Other answers:

\[\lg x(x+15) = 2\]
convert 2 to log 100
log x+log (x+15)=log(x(x+15))!!
it just a hint, so that both sides have log's :)
But how do you go from log(x(x+15)=2.. to x=5? I can't get that part
log(x(x+15))=2 log(x(x+15)=log100 cancel out the log, giving us : x(x+15)=100 or x^2+15x-100=0 solve for x by factorization or by complete square or by quadratic formula
got it ?
Yes! Just solved it.. thank you!
I didn't think of doing log 100 to cancel the logs on both sides

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