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Shaks

Show that the equation represents a circle by rewriting it in standard form, and find the center and radius of the circle. x2 + y2 + 4y + 2 = 0

  • one year ago
  • one year ago

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  1. Shaks
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    Show that the equation represents a circle by rewriting it in standard form, and find the center and radius of the circle. x2 + y2 + 4y + 2 = 0

    • one year ago
  2. Shaks
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    can u helpme

    • one year ago
  3. saifoo.khan
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    @Directrix are you good with circles?

    • one year ago
  4. Shaks
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    noup

    • one year ago
  5. Shaks
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    help mee

    • one year ago
  6. Shaks
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    sir

    • one year ago
  7. Shaks
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    helloo

    • one year ago
  8. Directrix
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    @Shaks I'm hoping you understand the process of completing the square. We'll need that to get x2 + y2 + 4y + 2 = 0 into the standard form of the equation of a circle. That standard form is (x - h) ^2 + (y - k) ^2 = r^2 where (h,k) are the coordinates of the center of the circle and r is the radius of the circle. Check out the attachment.

    • one year ago
  9. Shaks
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    is that the asnwer

    • one year ago
  10. Directrix
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    No. Focus on the process, not the answer.

    • one year ago
  11. Shaks
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    yeaa

    • one year ago
  12. Shaks
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    getting it kind it

    • one year ago
  13. Shaks
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    of

    • one year ago
  14. Shaks
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    The center is (0,-2)

    • one year ago
  15. Directrix
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    So, x^2 + y^2 + 4y + 2 = 0 can be written as x^2 + y^2 + 4y + __4_ = 0 + 4 (x + 0) ^2 + (y + 2) ^2 = 4 ---> Your Circle Now, look at the standard form for the circle equation, compare it to the equation, and pick out the coordinates of the center and the value of the radius. Post what you get, and I'll check. @Shaks

    • one year ago
  16. Directrix
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    r = ?

    • one year ago
  17. Shaks
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    x^2+(y+2)^2=3 is this the standerd form

    • one year ago
  18. Shaks
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    r= -2

    • one year ago
  19. Shaks
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    hello

    • one year ago
  20. Shaks
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    are u there

    • one year ago
  21. Directrix
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    r= -2 --> Incorrect

    • one year ago
  22. Shaks
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    then how to solve it

    • one year ago
  23. Directrix
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    Look at standard form for circle equation: That standard form is (x - h) ^2 + (y - k) ^2 = r^2 where (h,k) are the coordinates of the center of the circle and r is the radius of the circle. What positive number times itself = 4? That's your r.

    • one year ago
  24. Shaks
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    2 is r

    • one year ago
  25. Directrix
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    Correct.

    • one year ago
  26. Shaks
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    got it

    • one year ago
  27. Shaks
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    noo r is not 2

    • one year ago
  28. Shaks
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    is it 4

    • one year ago
  29. Directrix
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    @Shaks I messed up by dropping the 2. So, x^2 + y^2 + 4y + 2 = 0 can be written as x^2 + y^2 + 4y + __4_ = 2 + 4 = 6. r^2 = 6 and r is square root of 6.

    • one year ago
  30. Shaks
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    is it 6

    • one year ago
  31. Shaks
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    2.44

    • one year ago
  32. Directrix
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    6 = r^2. We want r which is square root of 3.

    • one year ago
  33. Shaks
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    hmm

    • one year ago
  34. Shaks
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    trying to understand

    • one year ago
  35. Shaks
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    1.7

    • one year ago
  36. Shaks
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    did not get it it too doficult

    • one year ago
  37. Shaks
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    difficult

    • one year ago
  38. Directrix
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    You approximated square root of 3 to get 1.7. I stick with exact form but I don't know what your options are.

    • one year ago
  39. Shaks
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    yaa i got it

    • one year ago
  40. Shaks
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    Find all real solutions of the equation. (Enter your answers as a comma-separated list. If there is no real solution, enter NO REAL SOLUTION.) x + 42 = x

    • one year ago
  41. Shaks
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    now 1 more sum

    • one year ago
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