meejoy
show that the sum of a complex number and its conjugate is twice the real part of the number, and the difference is twice the imaginary part of the number.
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manishsatywali
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do u knw what is complex no.?
manishsatywali
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let me know that first?
perl
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(a+bi) - (a-bi) = 2b i
meejoy
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@manishsatywali : yes i know it..
manishsatywali
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so fr the moment u have been provided that : for a complex no . A+ Bi
manishsatywali
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what will be it's conjugate ???? tell me asap
meejoy
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@perl : thanks..
meejoy
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@manishsatywali : a-bi
manishsatywali
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k now according to th equestion there r two conditions first diffrence and sum of complex no. and it's conjugate ......ok
perl
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oh i messed up the first one
perl
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(a+bi) + ( a-bi) = 2a
(a+bi) - (a-bi) = 2b i
manishsatywali
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frst let's focus on the sum of complex no. and it's conjugate
perl
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manish, dont sweat it bro. this is done
perl
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where is my medal?
perl
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(a+bi) + ( a-bi) = 2a
(a+bi) - (a-bi) = 2b i
manishsatywali
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@perl pls...dn't give direct answer...............i getting whether she everything about the question or not right from base level
meejoy
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@manishsatywali : i agree..
perl
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manish, dont sweat it bro.
perl
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manish, i got this bro
manishsatywali
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nw sum (A-Bi ) + (A-Bi).........do it fast ?????????????@meejoy
perl
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no thats wrong manish
perl
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manish, here
(a+bi) + ( a-bi) = 2a
(a+bi) - (a-bi) = 2b i
perl
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a = Re(z) , b = Im (z) ,
manishsatywali
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@perl bro pls. w8
manishsatywali
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@meejoy do the sum
perl
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ok sorry :) message me if you have question
meejoy
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@perl and @manishsatywali : this is for studying purpose... but it seems this just gave me a mess. >_<
manishsatywali
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@meejoy.........pls do the sum
meejoy
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@perl and @manishsatywali : stop the wild talk ..
perl
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wild talk?
meejoy
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2A-2Bi
manishsatywali
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srry @meejoy u gt the wrong answer
+ Bi and - Bi must cancel
meejoy
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you ask me to get the sum of this right ? (A-Bi ) + (A-Bi) .. how come that Bi must be cancel???
meejoy
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@manishsatywali : are you still here?
meejoy
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@perl : will you pls help me to know and understand the right answer and solution? thanks..
manishsatywali
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|dw:1359613917139:dw|
meejoy
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you give me (A-Bi ) + (A-Bi). and not (A+Bi ) + (A-Bi).
meejoy
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@manishsatywali : ok then???
manishsatywali
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so what is the answer it is 2A ( THIS IS REAL NO.) do u follow till here?
meejoy
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yes i know.. because a is the real part and bi is the imaginary part of the number.. :) ok @manishsatywali : no need to finish this i got it already :)) thanks
meejoy
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of the complex number. :)
manishsatywali
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k @meejoy will u nw do the difference on ur own?
manishsatywali
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mn tell me d answer ?
Directrix
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Given: x = a + bi where a and b are real numbers and i = square root of (-1).
The conjugate of x is a - bi.
The conjugate of the conjugate of x is a - (-bi) = a + bi which equals x which is a+bi.
Therefore, the conjugate of the conjugate of a+bi = a + bi.
Note: The sum of a number and its complex conjugate is zero.
meejoy
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@manishsatywali : yup :)
manishsatywali
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where is d answer ???????
meejoy
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@manishsatywali : 2bi.. are we done?? .. bayiee
meejoy
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@Directrix : oh thanks :)
manishsatywali
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yes we r done.........bye n thanks fr allowing me to help you ......
meejoy
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@manishsatywali : no reason to thank me .. i was the one who must thank you ...
manishsatywali
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k got i t
meejoy
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@manishsatywali : heres your medal :)