anonymous
  • anonymous
show that the sum of a complex number and its conjugate is twice the real part of the number, and the difference is twice the imaginary part of the number.
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
do u knw what is complex no.?
anonymous
  • anonymous
let me know that first?
perl
  • perl
(a+bi) - (a-bi) = 2b i

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anonymous
  • anonymous
@manishsatywali : yes i know it..
anonymous
  • anonymous
so fr the moment u have been provided that : for a complex no . A+ Bi
anonymous
  • anonymous
what will be it's conjugate ???? tell me asap
anonymous
  • anonymous
@perl : thanks..
anonymous
  • anonymous
@manishsatywali : a-bi
anonymous
  • anonymous
k now according to th equestion there r two conditions first diffrence and sum of complex no. and it's conjugate ......ok
perl
  • perl
oh i messed up the first one
perl
  • perl
(a+bi) + ( a-bi) = 2a (a+bi) - (a-bi) = 2b i
anonymous
  • anonymous
frst let's focus on the sum of complex no. and it's conjugate
perl
  • perl
manish, dont sweat it bro. this is done
perl
  • perl
where is my medal?
perl
  • perl
(a+bi) + ( a-bi) = 2a (a+bi) - (a-bi) = 2b i
anonymous
  • anonymous
@perl pls...dn't give direct answer...............i getting whether she everything about the question or not right from base level
anonymous
  • anonymous
@manishsatywali : i agree..
perl
  • perl
manish, dont sweat it bro.
perl
  • perl
manish, i got this bro
anonymous
  • anonymous
nw sum (A-Bi ) + (A-Bi).........do it fast ?????????????@meejoy
perl
  • perl
no thats wrong manish
perl
  • perl
manish, here (a+bi) + ( a-bi) = 2a (a+bi) - (a-bi) = 2b i
perl
  • perl
a = Re(z) , b = Im (z) ,
anonymous
  • anonymous
@perl bro pls. w8
anonymous
  • anonymous
@meejoy do the sum
perl
  • perl
ok sorry :) message me if you have question
anonymous
  • anonymous
@perl and @manishsatywali : this is for studying purpose... but it seems this just gave me a mess. >_<
anonymous
  • anonymous
@meejoy.........pls do the sum
anonymous
  • anonymous
@perl and @manishsatywali : stop the wild talk ..
perl
  • perl
wild talk?
anonymous
  • anonymous
2A-2Bi
anonymous
  • anonymous
srry @meejoy u gt the wrong answer + Bi and - Bi must cancel
anonymous
  • anonymous
you ask me to get the sum of this right ? (A-Bi ) + (A-Bi) .. how come that Bi must be cancel???
anonymous
  • anonymous
@manishsatywali : are you still here?
anonymous
  • anonymous
@perl : will you pls help me to know and understand the right answer and solution? thanks..
anonymous
  • anonymous
|dw:1359613917139:dw|
anonymous
  • anonymous
you give me (A-Bi ) + (A-Bi). and not (A+Bi ) + (A-Bi).
anonymous
  • anonymous
@manishsatywali : ok then???
anonymous
  • anonymous
so what is the answer it is 2A ( THIS IS REAL NO.) do u follow till here?
anonymous
  • anonymous
yes i know.. because a is the real part and bi is the imaginary part of the number.. :) ok @manishsatywali : no need to finish this i got it already :)) thanks
anonymous
  • anonymous
of the complex number. :)
anonymous
  • anonymous
k @meejoy will u nw do the difference on ur own?
anonymous
  • anonymous
mn tell me d answer ?
Directrix
  • Directrix
Given: x = a + bi where a and b are real numbers and i = square root of (-1). The conjugate of x is a - bi. The conjugate of the conjugate of x is a - (-bi) = a + bi which equals x which is a+bi. Therefore, the conjugate of the conjugate of a+bi = a + bi. Note: The sum of a number and its complex conjugate is zero.
anonymous
  • anonymous
@manishsatywali : yup :)
anonymous
  • anonymous
where is d answer ???????
anonymous
  • anonymous
@manishsatywali : 2bi.. are we done?? .. bayiee
anonymous
  • anonymous
@Directrix : oh thanks :)
anonymous
  • anonymous
yes we r done.........bye n thanks fr allowing me to help you ......
anonymous
  • anonymous
@manishsatywali : no reason to thank me .. i was the one who must thank you ...
anonymous
  • anonymous
k got i t
anonymous
  • anonymous
@manishsatywali : heres your medal :)

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